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elixir [45]
3 years ago
15

If a block of copper is 5 cm by 10 cm by 3 cm and has a mass of 1335 grams, what is the density of copper?

Mathematics
2 answers:
dedylja [7]3 years ago
7 0

Answer:

the density of copper is 90.03g/cm³

Step-by-step explanation:

This problem bothers on the density of a substance, this case for a copper material

Given data

Mass of copper m = 1355g

Volume of copper block v= l*b*h

10*5*3=150cm³

We know that the density

ρ= mass/volume

ρ= 1355/150

ρ= 90.03g/cm²

The density of a substance is defined as the mass of the substance per unit volume

stepan [7]3 years ago
4 0

Answer:

The answer is 8.9 gm/cm cubed

Step-by-step explanation:

Just did it on algebra nation

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2. The sum of the reciprocals of two consecutive positive integers is 17/72. Write an equation that can be used to find the two
Lena [83]
To answer this item, we let x be the first positive integer. Then, the second would be x+1. Their reciprocals would be 1/x and 1/(x+1). Then, the equation that would best represent the scenario above is,
                            1/x + 1/(x+1) = 17/72
Solving the equation above,
                           ((x+1) + x) / (x)(x+1) = 17/72
If we take the numerators of both sides of the equation,
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The value of x from the equation is 8 and x+1 would be 9. Thus, the answer would be 8 and 9. 
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3 years ago
The company calculates that 500 g of titanium dioxide should produce 1.2 kg of titanium chloride. However, the company finds tha
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Answer:

75%

Step-by-step explanation:

Percent yield = experimental yield / theoretical yield * 100

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= 75

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3 years ago
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3 years ago
Two sets of three consecutive integers have a property that the product of the larger two is
skelet666 [1.2K]

Answer:

{1, 2, 3},  {3, 4, 5}

Step-by-step explanation:

Write expressions for three consecutive integers:  n, n + 1, n + 2.

Set up an equation for the verbal description: the product (mulitplication) of the two larger integers (the last two) is one less than 7 times the smallest (the first one).

(n + 1)(n + 2) = 7n - 1

Multiply (FOIL) the left side.

n^2 + 3n + 2 = 7n - 1

Subtract 7n and subtract 1 to make the right side 0.

n^2 - 4n + 3 = 0

Factor.

(n - 1)(n - 3) = 0

Set the two factors equal to 0

n - 1 = 0,  n - 3 = 0

Solve for n.

n = 1,  n = 3

One set of integers begins with 1, so it's {1, 2, 3}.

The other set begins with 3, so it's {3, 4, 5}

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