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Katyanochek1 [597]

3 years ago

10

Consider the line - 3x + 7y=4.

1 answer:

Verdich [7]3 years ago

5 0

Answer:

Parallel: y = 3/7x - 17/7

Perpendicular: y = -7/3x - 11

Step-by-step explanation:

Rearrange the given equation so that it is in slope-intercept form.

-3x + 7y = 4

7y = 3x + 4

y = 3/7x + 4/7

The slope of the line is 3/7. A parallel line will have the same slope. Using this slope and the given point, you can find an equation using point-slope form.

y - y₁ = m(x - x₁)

y - (-4) = 3/7(x - (-3))

y + 4 = 3/7(x + 3)

y + 4 = 3/7x + 9/7

y = 3/7x - 17/7

A perpendicular line will have a slope that is the negative inverse of the original slope. This means that the slope will be -7/3. Repeat above steps.

y - y₁ = m(x - x₁)

y - (-4) = -7/3(x - (-3))

y + 4 = -7/3(x + 3)

y + 4 = -7/3x - 7

y = -7/3x - 11

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Find x and y. <br><br> pls pls help

Anna [14]

Answer:

x = 65 , y = 64

Step-by-step explanation:

y - 16 and 2y + 4 are same- side interior angles and sum to 180° , that is

y - 16 + 2y + 4 = 180

3y - 12 = 180 ( add 12 to both sides )

3y = 192 ( divide both sides by 3 )

y = 64

then

2y + 4 = 2(64) + 4 = 128 + 4 = 132

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

2y + 4 is an exterior angle of the triangle , then

x + 67 = 132 ( subtract 67 from both sides )

x = 65

7 0

2 years ago

PLEASE HELP ME . how can the converse of the Pythagorean theorem help you determine whether the roped off area is in the shape o

trapecia [35]

Step-by-step explanation:

From the Pythagorean theorem we have:

$a^2+b^2=c^2$ <em>subtract b² from both sides</em>

$a^2=c^2-b^2\to a=\sqrt{c^2-b^2}$

Same:

$b=\sqrt{c^2-a^2}$

4 0

4 years ago

See attached picture, is there a way to enter equations or algebraic symbols?

coldgirl [10]

SOLUTIONS

Solve a given equations or algebraic symbols?

$\begin{gathered} f(x)=x^2+2x \\ g(x)=1-x^2 \end{gathered}$

(A)

$\begin{gathered} (f+g)(x)=(x^2+2x)+(1-x^2) \\ collect\text{ like terms} \\ x^2-x^2+2x+1 \\ (f+g)(x^)=2x+1 \end{gathered}$

(B)

$\begin{gathered} (f-g)(x)=(x^2+2x)-(1-x^2) \\ =x^2+2x-1+x^2 \\ =x^2+x^2+2x-1 \\ (f-g)(x)=2x^2+2x-1 \end{gathered}$

(C)

$\begin{gathered} fg(x)=(x^2+2x)(1-x^2) \\ =x^2-x^4+2x-2x^3 \\ fg(x)=-x^4-2x^3+x^2+2x \end{gathered}$

(D)

$\begin{gathered} \frac{f}{g}(x)=(x^2+2x)\div(1-x^2) \\ =\frac{x^2+2x}{1-x^2} \end{gathered}$

5 0

2 years ago

Which of these is the standard form of the following function?

Step2247 [10]

I’m pretty sure the answer would be B

3 0

3 years ago

Read 2 more answers

PLEASE PLEASE HELP I WILL GIVE BRAINIEST! SOS!<br> What's 1+1<br> please help

alexandr402 [8]

Answer:

The answer is 2.

Step-by-step explanation:

If I have done my math correctly, and I think I have, 1+1 should equal 2. Hope this helps ;)

8 0

3 years ago

Read 2 more answers