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kobusy [5.1K]
3 years ago
15

Main st. Auto has 9 cars and 4 trucks

Mathematics
1 answer:
Dahasolnce [82]3 years ago
3 0

Answer:

Main St.: 54 cars

Airport: 40 cars

Main St. Auto has more car

Step-by-step explanation:

First divide the total number of trucks (24) by the number of trucks the mentioned.  

Main St.: 24/4= 6   Airport: 24/3=8

Now multiply your answers by the number of cars.

Main St: 9 x 6 =54  Airport: 5 x 8= 40

Main St. Would have 54 cars when they have 24 trucks while Airport will have 40 cars when they have 24 trucks.

Meaning Main st. has more cars.


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MissTica
6 + 8 = 14.

You have 6, then just count up 8 times, and then you will get 14.
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5x+2y=9, and 5x+10y=75,
MatroZZZ [7]

Answer:

x = -1.5 y = 8.25

Step-by-step explanation:

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Help please!<br> Sorry for the image quality.
VARVARA [1.3K]

Answer:

\displaystyle (-1,\frac{-3}{2})

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Midpoint Formula: \displaystyle (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

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Point (1, -4)

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  1. Substitute [MF]:                         \displaystyle (\frac{-3+1}{2},\frac{1-4}{2})
  2. [Fractions] Add/Subtract:         \displaystyle (\frac{-2}{2},\frac{-3}{2})
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8 0
2 years ago
Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .
Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of F around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

           F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle

Therefore,

                  P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y

Let's calculate the needed partial derivatives.

                              P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0

Thus,

                                    Q_x -P_y = 0 -2 = - 2

Now, by the Green's theorem, we have

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4 0
2 years ago
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