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3 years ago

10

Evaluate (9^1/2) over (4^-1/2)????

1 answer:

erik [133]3 years ago

5 0

Using laws of exponents,

9^(1/2) = 34^(-1/2) = (1/4)^(1/2) = 1/2

Therefore,9^(1/2)/(4^(-1/2)) = 3/(1/2) = 6.

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If an integer n has three unique prime divisors, then it follows that the largest prime divisor of n is less than or equal to cu

TiliK225 [7]

Answer:

False

Step-by-step explanation:

Lets call the three prime divisors of n p, q, and r, being r the largest, we know:

$n=q * p * r$

Now, if

$q * p < r$

then

$n < r * r = r^2$

So:

$\sqrt{n} < \sqrt{r^2} = r$

Also, for every natural greater than one, we know:

$\sqrt[3]{n}$

so

$\sqrt[3]{n}$

from which:

$\sqrt[3]{n} < r$

So, we see, this means the preposition is false, we can find a particular counterexample:

q=2

p=3

p*q = 6

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4 0

4 years ago

Evaluate when a = 8 and b = 4. <br><br> ab^2<br> a−b

eduard

<span>Evaluate when a = 8 and b = 4.

ab^2
a−b

ab² = (8)(4)² = 8*16= 128

a - b = 8 - 4 = 4 </span>

3 0

3 years ago