Answer:
2000 problems
Step-by-step explanation:
1st week - 0.25x
2nd week - 1.10(0.25x)
3rd week - 0.6(0.25x + 1.10(0.25x))
4th week - 320
Than to solve for the monthly quota, equate the sum of all the problems solved to x and determine its value. Thus, the students solved 2000 problems all in all.
Enjoy Your Answer!
Now we use FOIL to rewrite the expression.
FOIL is:
First
Outer
Inner
Last
That's the order we will be distributing the variables in the parentheses.
Combine like terms:
That's your final answer.
Hope that helps.
She read 242 pages. I got that by finding what (4/5) x (360) was which is 288 and then subtracted 46 to see what was left over which is 242
Answer:
Step-by-step explanation:
→ First look at the first term of each expression and see if they can be simplified, and they can
→ Now look at the a terms, since a larger one is at the top, you subtract
→ Now simplify the b and c terms
Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
