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3 years ago

8

How do I solve for x?

2 answers:

7nadin3 [17]3 years ago

7 0

3) y= 5x-6
Add 6 to both sides so it's gonna be=
6y = 5x
Then divde by 5 in both sides so it's gonna be:
6y/5 = x

4) (x+y)/3 = 5
Multiply by 3 in both sides so it's gonna be:
x+y = 15
Then subtract by y to move it to the other side so it's gonna be: x = 15-y
Hope this helps

zheka24 [161]3 years ago

3 0

3.) 5x-6=0, Add 6 to either side -> 5x=6, divide each side by 5 -> x=6/5 ---- 4.) x+y/3=5, multiple each side by 3 -> x+y=15, move y to the other side -> x=-y+15

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Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

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Replacing y with and x with y:

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Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

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$a^{-1}(x)$ = $a(x)$ Hence, II is true.

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Replacing y with and x with y:

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Replacing y with and x with y:

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<em>Correct answer:</em>

<em>A. I and II</em>

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