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7nadin3 [17]
3 years ago
8

How do I solve for x?

Mathematics
2 answers:
7nadin3 [17]3 years ago
7 0
3) y= 5x-6
Add 6 to both sides so it's gonna be=
6y = 5x
Then divde by 5 in both sides so it's gonna be:
6y/5 = x

4) (x+y)/3 = 5
Multiply by 3 in both sides so it's gonna be:
x+y = 15
Then subtract by y to move it to the other side so it's gonna be: x = 15-y
Hope this helps
zheka24 [161]3 years ago
3 0
3.) 5x-6=0, Add 6 to either side -> 5x=6, divide each side by 5 -> x=6/5 ---- 4.) x+y/3=5, multiple each side by 3 -> x+y=15, move y to the other side -> x=-y+15
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What is the solution to the equation below? <br> 5 - n/2 = 12
Zarrin [17]

Step-by-step explanation:

5 - n/2 = 12

10/2 - n/2 = 12

n = (12 × (-2)) + 10

n = (-24) + 10

n = <u>-1</u><u>4</u>

Let's prove it :

5 -  ( - \frac{14}{2} )  \\ =   \frac{10}{2}  +  \frac{14}{2}  \\  = \frac{24}{2}   \\  = 12

Conclusion :

5 - n/2 = 12

5 - (-14/2) = 12

and

n = -14

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Step-by-step explanation:

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IgorLugansk [536]

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What is ⅓ divided by ¼? Use the model if needed. Answer should be in simplest form. Explain your answer
Misha Larkins [42]

Answer:

The answer to the expression in simplest form is:

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Step-by-step explanation:

Given the function

\frac{\frac{1}{3}}{\frac{1}{4}}

solving to get the simplest form

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\cdot \:d}{b\cdot \:c}

\frac{\frac{1}{3}}{\frac{1}{4}}=\frac{1\cdot \:4}{3\cdot \:1}

\mathrm{Apply\:rule}\:a\cdot 1=a

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Thus, the answer to the expression in simplest form is:

\frac{\frac{1}{3}}{\frac{1}{4}}=\frac{4}{3}

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