Question

Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2 EndFraction comma StartFraction negative 5 + StartRoot 13 EndRoot Over 2 EndFraction StartFraction 5 minus StartRoot 13 EndRoot Over 2 EndFraction comma StartFraction 5 + StartRoot 13 EndRoot Over 2 EndFraction 5, 0

Answer 1

Given:

The quadratic equation is $x^{2}=-5 x-3$

We need to determine the solutions of the quadratic equation.

Solution:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

$x^{2}+5 x+3=0$

The solution of the equation can be determined using quadratic formula.

Thus, we get;

$x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}$

$x=\frac{-5 \pm \sqrt{25-12}}{2 }$

$x=\frac{-5 \pm \sqrt{13}}{2 }$

Thus, the two roots of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

Hence, the solutions of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

Answer 2

Answer: B

Step-by-step explanation:

it is B