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sveta [45]
3 years ago
6

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

ct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Write the quadratic equation in factored form. Be sure to write the entire equation.

x 2 + x - 12 = 0

Mathematics
1 answer:
LuckyWell [14K]3 years ago
3 0

Answer:

(X+3) (x-3)

Step-by-step explanation:

The complete solution is given in attachment below

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(HELP) what is 10 1/2 ÷ 9 2/6 = ? (show ur work)
Readme [11.4K]

Answer:

9/8 or 1.125

Step-by-step explanation:

10 1/2 ÷ 9 2/6

= 21/2 ÷ 56/6

= 9/8

= 1.125

=》 See the attachment.

Hope it helps ⚜

8 0
2 years ago
Read 2 more answers
(-9) - 9n= (-45) please helpppp!
kozerog [31]

Answer: n=4

Step-by-step explanation:

\left(-9\right)-9n=\left(-45\right)

add 9 to both sides

-9-9n+9=-45+9

-9n=-36

divide both sides by -9

n=4

Brainliest please

8 0
3 years ago
Read 2 more answers
Multiply the following and simplify.
Yuki888 [10]
What are we multiplying exactly?
5 0
3 years ago
The x values are the
dem82 [27]
The horizontal value in a pair of coordinates: how far along the point is. The X Coordinate is always written first in an ordered pair of coordinates (x,y), such as (12,5). In this example, the value "12" is the X Coordinate. Also called "Abscissa"
4 0
3 years ago
Consider the given matrix. 1 −1 0 5 1 4 0 1 1 Find the eigenvalues. (Enter your answers as a comma-separated list.) λ = Find the
fomenos

Answer:

Step-by-step explanation:

We have to diagonalize the matrix

\left[\begin{array}{ccc}1&-1&0\\5&1&4\\0&1&1\end{array}\right]

we have to solve the expression

|A-\lambda I|=0

Thus, by applying the determinant we obtain the polynomial

(1-\lambda )^3+5-4=0\\(1-\lambda )^3+1=0\\

-\lambda^3+3\lambda^2-4\lambda+2

\lambda_1=1\\\lambda_2=1-i\\\lambda_3=1+i\\

and the eigenvector will be

v_1=(-4,0,5)\\v_2=(-1,-i,-1)\\v_3=(-1,i,1)

HOPE THIS HELPS!!

3 0
3 years ago
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