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BabaBlast [244]
3 years ago
9

Ryan is going to make a sculpture from a rectangular block of clay. The

Mathematics
1 answer:
Elden [556K]3 years ago
7 0
Length=(x+3)
Breadth=(x-3)
Height=(2x-5)
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4 0
3 years ago
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HELP PLZ PICK ONE OF THE ONES SHOWN:
defon

I am doing with Question Number 2

Let the two numbers be 'x' and 'y'.

According to the question, the product of two numbers is 14.

x \times y=14

So, xy=14 (Equation 1)

Now, one of the numbers is 3 ½ times the other.

So, x = 3\frac{1}{2}\times y

x=\frac{7}{2}y (Equation 2)

Substituting the value of 'x' from equation 2 in equation 1, we get

\frac{7}{2}y \times y = 14

\frac{7}{2}y^{2} = 14

y^{2} = 4

So, y= 2 and -2

So, x=\frac{14}{2} and x=\frac{14}{-2}

x=7 and -7

Numbers are 2,7 and -2,-7.

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Sum of numbers -2 and -7 = -9.


6 0
3 years ago
What are the possible numbers of positive, negative, and complex zeros of f(x) = −3x4 −
Anna007 [38]

Answer:

b.

Step-by-step explanation:

We have to look at sign changes in f(x) to determine the possible positive real roots.

f(x)=-3x^4-5x^3-x^2-8x+4

There is only one sign change here, between the -8x and the +4.  So that means there is only 1 possible real positive root.

Now we have to look at sign changes in f(-x) to determine the possible negative real roots.

f(-x)=-3x^4+5x^3-x^2+8x+4

There are 3 sign changes here.  That means there are either 3 negative roots or 3-2 = 1 negative root.  So we have:

1 positive

3 or 1 negative

We need to pair them up now with all the possible combinations.

If we have 1 positive and 1 negative, we have to have 2 imaginary

If we have 1 positive and 3 negative, we have to have 0 imaginary

Keep in mind that the total number or roots--positive, negative, imaginary--have to add up to equal the degree of the polynomial.  This is a 4th degree polynomial, so we will have 4 roots.

7 0
3 years ago
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