7a+7b+77
I I hope this helps you
Answer:
a) 22497.7 < μ< 24502.3
b) With 99% confidence the possible error will not exceed 1002.3
Step-by-step explanation:
Given that:
Mean (μ) = 23500 kilometers per year
Standard deviation (σ) = 3900 kilometers
Confidence level (c) = 99% = 0.99
number of samples (n) = 100
a) α = 1 - c = 1 - 0.99 = 0.01
Using normal distribution table, 
is the z value of 1 - 0.005 = 0.995 of the area to the right which is 2.57.
The margin of error (e) is given as:
The 99% confidence interval = (μ - e, μ + e) = (23500 - 1002.3, 23500 + 1002.3) = (22497.7, 24502.3)
Confidence interval = 22497.7 < μ< 24502.3
b) With 99% confidence the possible error will not exceed 1002.3
<h3>Answer:
10000 in base 5</h3>
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Explanation:
4+1 = 5 in base 10
But in base 5, the digit "5" does not exist.
The only digits in base five are: 0, 1, 2, 3, 4
This is similar to how in base ten, the digits span from 0 to 9 with the digit "10" not being a thing (rather it's the combination of the digits "1" and "0" put together).
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Anyways let's go back to base 5.
Instead of writing 4+1 = 5, we'd write 4+1 = 10 in base 5. The first digit rolls back to a 0 and we involve a second digit of 1.
Think how 9+1 = 10 in base 10.
Similarly,
44+1 = 100 in base 5
444+1 = 1000 in base 5
4444+1 = 10000 in base 5
and so on.
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Here are the first few numbers in base 5, when counting up by 1 each time.
0, 1, 2, 3, 4,
10, 11, 12, 13, 14,
20, 21, 22, 23, 24,
30, 31, 32, 33, 34,
40, 41, 42, 43, 44,
100, 101, 102, 103, ...
Notice each new row is when the pattern changes from what someone would expect in base 10. This is solely because the digit "5" isn't available in base 5.
