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3 years ago

I need help on number 8

Mathematics

1 answer:

tester [92]3 years ago

5 0

Answer:

(-3,5) (-3,4)

5-4/-3--3=1/0

It is a vertical line so it's y∈R

Step-by-step explanation:

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What is the rule for the pair?

mylen [45]

2
to work it out just go output f (x) - input x so, 3 - 1 = 2 and double check this using your next equations 4 - 2 = 2

5 0

3 years ago

Which shows the expression below simplified? 0.00048 - (3.4 × 10-5) A. 4.46 × 10-4 B. 3.39952 × 10-5 C. 4.46 × 10-5 D. 1.4 × 10-

MakcuM [25]

Option C

The simplified form of given expression is $4.46 \times 10^{-4}$

Solution:

Given that we have to simplify the expression shown below

$0.00048 - (3.4 \times 10^{-5})$

Let us first convert 0.00048 to scientific notation

Steps to follow:

Move the decimal point in your number until there is only one non-zero digit to the left of the decimal point. The resulting decimal number is a.

Count how many places you moved the decimal point. This number is b.

If you moved the decimal to the left b is positive.

If you moved the decimal to the right b is negative.

If you did not need to move the decimal b = 0.

Write your scientific notation number as a x 10^b and read it as "a times 10 to the power of b."

Remove trailing 0's only if they were originally to the left of the decimal point.

$0.00048 = 4.8 \times 10^{-4}$

So the given expression becomes,

$\rightarrow 4.8 \times 10^{-4} - 3.4 \times 10^{-5}$

Let us make the exponent of second term as -4

$\rightarrow 4.8 \times 10^{-4} - 0.34 \times 10^{-4}$

Take $10^{-4}$ as common term,

$\rightarrow 10^{-4} (4.8 - 0.34)$

$\rightarrow 4.46 \times 10^{-4}$

Thus option C is correct

7 0

3 years ago

Please help! A-level maths.

astra-53 [7]

$x+y=k\implies y=k-x$

Substitute this into the parabolic equation,

$k-x=6-(x-3)^2\implies x^2-7x+(k+3)=0$

We're told the line $x+y=k$ intersects $C$ twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

$(-7)^2-4(k+3)=49-4(k+3)>0\implies k$

We can tell from the quadratic equation that $C$ has its vertex at the point (3, 6). Also, note that

$-1\le\sin t\le1\implies3\le3+2\sin t\le5\implies3\le x\le5$

and

$-1\le\cos2t\le1\implies2\le4+2\cos2t\le6\implies2\le y\le6$

so the furthest to the right that $C$ extends is the point (5, 2). The line $x+y=k$ passes through this point for $2+5=k\implies k=7$ . For any value of $k$ , the line $x+y=k$ passes through $C$ either only once, or not at all.

So $7\le k$ ; in set notation,

$\{k\mid 7\le k$

4 0

3 years ago

Which equation could represent the relationship shown in the scatter plot? y=−3x−2

Orlov [11]

Answer:

Y=-3/4x + 10

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

I need help... on my homework it says to write each expression in radical form, or write each radical and exponential form . For

pantera1 [17]

$\bf ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt{13}\implies \sqrt[2]{13^1}\implies 13^{\frac{1}{2}}$

5 0

3 years ago

I need help on number 8​

I need help on number 8