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Oxana [17]
2 years ago
7

Solve j ÷ 3 1/2 for j= 9/10A) 4 1/5B) 3 3/10C) 9/35

Mathematics
1 answer:
emmasim [6.3K]2 years ago
5 0
The answer is C) 9/35.
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Jamal watched his older brother Robert lift weights. The bar alone had a mass of 20 kg. on the bar he had two 11.4 weights, two
Leto [7]
What you have to do is add them all!
   20   bar
11.4   2 11.4 weights
11.4
  4.5   2 4.5 weights
  4.5
450.0   4 450 weights
 450.0
 450.0
+450.0
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        1.8
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3 years ago
What goes in the blank boxes
noname [10]

Answer:

Everything

Step-by-step explanation:

We can keep every things in the blank boxes.

7 0
3 years ago
Use the real zeros to factor f x^4 plus 10^3 minus 20x^2 minus 90x plus 99
Furkat [3]

Answer:

f(x) = (x + 11) (x + 3) (x − 1) (x − 3)

Step-by-step explanation:

f(x) = x⁴ + 10x³ − 20x² − 90x + 99

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±99, ±11, ±9, ±3, ±1

By trial and error, the zeros are -11, -3, 1, and 3.

f(x) = (x + 11) (x + 3) (x − 1) (x − 3)

7 0
3 years ago
Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?
Tema [17]

Answer:

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

Step-by-step explanation:

We are given that

f(x)=tan(x)-\frac{2}{x}

g(x)=x^2+8

We have to find f(x)\times g(y)

To find the value of f(x)\times g(y) we will multiply f(x) by g(y)

g(y)=y^2+8

Now,

f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)

f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

Hence,

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

5 0
2 years ago
A truck with a heavy load drove from Boston to New York at 45 mph. After unloading, it returned from New York to Boston at a spe
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Average speed is 53
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2 years ago
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