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padilas [110]
3 years ago
7

HELP ASAP!! No links or photos please. Don't answer if you don't know it

Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

b no

Step-by-step explanation:

c^2 =\sqrt{a {}^{2}  +b {}^{2}} 9 + 25 \: is \: not  =81

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The slope is <em>1.5/4.5</em>.

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This table shows temperatures in an Arctic city during
ioda

According to the temperature changes, it is found that:

  • On Tuesday, the temperature at Noon was of -28.5 ºF.
  • On Wednesday, the temperature at Midnight was of -5.5 ºF.
  • On Thursday, the change was of -11.8 ºF.
  • On Friday, the temperature at Noon was of -4.5 ºF.

<h3>What is the temperature change?</h3>
  • The temperature change during a period is given by the <u>temperature at the end of the period subtracted by the temperature at the start of the period</u>.

On Tuesday:

  • At the start of the period, the temperature was of -17.5 ºF.
  • The change was of -11 ºF.

Hence:

-11 = T_N - T_M

-11 = T_N + 17.5

T_N = -28.5

On Tuesday, the temperature at Noon was of -28.5 ºF.

On Wednesday:

  • At the end of the period, the temperature was of 10 ºF.
  • The change was of 15.5 ºF.

Hence:

15.5 = 10 - T_M

T_M = -5.5

On Wednesday, the temperature at Midnight was of -5.5 ºF.

On Thursday:

  • At the end of the period, the temperature was of -24 ºF.
  • At the start of the period, the temperature was of -12.2 ºF.

Hence:

C = -24 - (-12.2) = -24 + 12.2 = -11.8

On Thursday, the change was of -11.8 ºF.

On Friday:

  • At the start of the period, the temperature was of -21.8 ºF.
  • The change was of 17.3 ºF.

Hence:

17.3 = T_N - T_M

17.3 = T_N + 21.8

T_M = -4.5

On Friday, the temperature at Noon was of -4.5 ºF.

You can learn more about change at brainly.com/question/24313700

8 0
3 years ago
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