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attashe74 [19]
2 years ago
9

How many significant numbers are in 15,000

Mathematics
2 answers:
padilas [110]2 years ago
8 0
There are 2 if no decimal point is provided
timofeeve [1]2 years ago
6 0
15,000 has 2 significant figures. 
<span>1050 has 3 significant figures. </span>
<span>0.350 has 3 significant figures. </span>
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There are 6 dogs, 2 mice, and 4 cats. Write two sentences that describe a ratio of types of animals in this collection.
Marianna [84]
I’m sorry I’m dumb from the head
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3 years ago
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p: If two out of five people use the subway every day, then the probability of a person using the subway is 0.4.
Alexandra [31]

2 divided by 5 = 0.4

 so that statement is true.

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3 years ago
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Pls helppp very easy c:
Zielflug [23.3K]

Answer:

2 56 0 56 18 0 3 0 20 12 12 54 7 64 18 25 24 0 0 28 14 8 6 24 35 9 27 48 40 1 0 3 18 16 8 7 0 0 36 48 49 28 40 42 15 6 27 16 36 8 0 32 81 4 30 0 0 9 32 10 30 2 45 16 5 0 0 14 35 18 0 54 0 12 36 24 4 8 10 18 72 6 63 12 0 21 0 24 63 0 21 20 9 15 45 0 6 72 5 4

Step-by-step explanation:

This hurt my soul but enjoy

7 0
2 years ago
Chang used a coordinate plane to show where his posters are displayed on his bedroom wall. Three posters are located at E(5, 3),
arlik [135]

Answer:

EF = 9

GF = 2

Step-by-step explanation:

For EF, we want to find the distance between their c coordinates, since their y coordinates are the same. We want the distance between -4 and 5, which when you add their distance from 0, is 9.

For GF, they share the same x coordinate, so you're finding the distance between their y coordinates, which are 3 and 5. The distance between the two is 2, so the length of GF is 2.

5 0
3 years ago
How do you do this question?
AfilCa [17]
<h3>4 Answers: A, B, C, D</h3>

=======================================================

Explanation:

f(x) is continuous when x >= 1. The only discontinuity for f(x) is when x = 0, but 0 is not part of this interval.

f(x) is positive for any valid x value in the domain since x^6 is always positive. In general, x^n is positive for all x when n is any even number.

f(x) is decreasing. You can see this through a table of values or through a graph. For anything in the form 1/(x^k), it will be a decreasing function because x^k gets larger, so 1/(x^k) gets smaller, when x goes to infinity.

--------------------

The conditions to use the integral test have been met. So we have to see if \displaystyle \int_1^{\infty}f(x)dx converges or not.

Let's integrate and find out

\displaystyle \int \frac{1}{x^6} dx = \int x^{-6} dx\\\\\\ \displaystyle \int \frac{1}{x^6} dx = \frac{1}{1+(-6)}x^{-6+1}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = \frac{1}{-5}x^{-5}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = -\frac{1}{5}*\frac{1}{x^5}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = -\frac{1}{5x^5}+C\\\\

So we have

\displaystyle g(x) = \int f(x) dx\\\\\\\displaystyle g(x) = \int \frac{1}{x^6} dx\\\\\\\displaystyle g(x) = -\frac{1}{5x^5}+C\\\\\\

Meaning that,

\displaystyle \int_{a}^{b} f(x) dx = g(b)-g(a)\\\\\\\displaystyle \int_{a}^{b} \frac{1}{x^6} dx = \left(-\frac{1}{5b^5}+C\right)-\left(-\frac{1}{5a^5}+C\right)\\\\\\\displaystyle \int_{a}^{b} \frac{1}{x^6} dx = -\frac{1}{5b^5}+\frac{1}{5a^5}\\\\\\

If we plug in a = 1 and apply the limit as b approaches positive infinity, then the expression -\frac{1}{5b^5}+\frac{1}{5a^5} will turn into \frac{1}{5}

Therefore,

\displaystyle \int_{1}^{\infty} \frac{1}{x^6} dx = \frac{1}{5}\\\\\\

Because this integral converges, this means the series \displaystyle \sum_{n=1}^{\infty}\frac{1}{n^6} also converges as well by the integral test.

7 0
2 years ago
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