Answer:
C. 3 & -6
Step-by-step explanation:
x² + 3x -18 = 0
x² + 6x - 3x - 18 = 0
(x + 6)(x - 3) = 0
Answer:
Step-by-step explanation:
did u try seaching the answer?
Here u go, i hope this helped
Just subtract the 1st equation from the 2nd, as follows:
<span> 3x+6y=33
-(</span>3x+4y=19)
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2y= 14, and y = 7. Sub 7 for y in either of the original equations to obtain the value of x. Write your answer in the form (x, 7).
Answer:
(-3, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations by substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
x = 2y - 5
-2x + 5y = 11
<u>Step 2: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: -2(2y - 5) + 5y = 11
- Distribute -2: -4y + 10 + 5y = 11
- Combine like terms: y + 10 = 11
- Isolate <em>y</em>: y = 1
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define original equation: x = 2y - 5
- Substitute in <em>y</em>: x = 2(1) - 5
- Multiply: x = 2 - 5
- Subtract: x = -3