Which transformations were used to create congruent triangle E’F’G from triangle EFG?
1 answer:
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Answer:
79.4° to the nearest tenth of a degree
Step-by-step explanation:
You are trying to find the angle opposite the side of length 27.
Let the length of that side be c and a and b be the lengths of the other two sides and let C be the measure of the angle you are looking for
Using the law of cosines
729 = 361 + 529 - 874cosC
729 = 890 - 874cosC
-161 = -874cosC
-161/-874 = cosC
.1842105.... = cosC
C = arccos .1842105.... = 79.4° to the nearest tenth of a degree