Answer:
length of a rectangle is 5 more than twice the length. I believe
you mean the length of a rectangle is 5 more than twice the
width.
From the information given we can make two equations,
thus forming a system to solve. We know the perimeter
of a rectangle is 2(length + width) and area = length*width.
length of a rectangle is 5 more then twice the width:
L = 2w + 5
The perimeter is 130:
2(L+w) = 130
L+w = 65
Since we know L=2w+5 we can substitute that into 2nd equation
to solve for w
2w + 5 + w = 65
3w = 60
w = 20
L = 2w+5 = 45
The area is length*width = 20(45) = 900 square units
Answer:
7
^2
⋅
7
^4 = 49^6
Step-by-step explanation:
.7 & .700 are the same number
Answer:
Cost of bolts = x = $0.3
Cost of washers = y = $0.167
Step-by-step explanation:
Let us represent:
Cost of bolts = x
Cost of washers = y
Luke buys 4 bolts and 6 washers for $2.20
Hence:
4x + 6y = 2.20....Equation 1
Holly spends $1.80 on 3 bolts and 5 washers at the same local hardware store.
3x + 5y = 1.80....Equation 2
Combining both Equations
4x + 6y = 2.20....Equation 1
3x + 5y = 1.80....Equation 2
Multiply Equation 1 by 3 and Equation 2 by 4 to eliminate x
12x + 18x = 6.6.....Equation 4
12x + 20x = 7.2.......Equation 5
Substract Equation 4 from 5
= 2x = 0.6
x = 0.6/2
x = $0.3
Solving for y
4x + 6y = 2.20....Equation 1
4 × 0.3 + 6y = 2.2
1.2 + 6y = 2.2
6y = 2.2 - 1.2
6y = 1.0
y = 1.0/6
y = $0.167
Cost of bolts = x = $0.3
Cost of washers = y = $0.167
Answer:
A
35 60 65 70 90
Q1 = 60, Q3 = 70, Q3 - Q1 = 10
Low suspected outliers : 10 x 1.5 = 15
range, 60 -15 = 45
70 + 15 = 85
Hence, there are low suspected outliers i.e 35 and 90
