![\cos(3 \div 11) = \sec( \frac{1}{3 \div 11} )](https://tex.z-dn.net/?f=%20%5Ccos%283%20%5Cdiv%2011%29%20%20%3D%20%20%5Csec%28%20%5Cfrac%7B1%7D%7B3%20%5Cdiv%2011%7D%20%29%20)
so the first option: sec A = 11 over 3
Answer:
The correct answer is:
To subtract an integer, add its opposite; -4 + 5 = 1
Step-by-step explanation:
Marty is explaining to Susan how to solve the following problem, -4 – (-5)
He told Susan that to subtract an integer, add its opposite.
We know that whenever we solve the two terms, first we multiply the signs.
It means that the negative sign outside the round bracket will be multiplied with the negative sign of -5
That is,
-4 - (-5)
By multiplying the signs we get the terms:
-4 + 5
=1
Thus the correct option is D....
Ok,
divide by 2 on both sides...
![X = 3/4 * 2](https://tex.z-dn.net/?f=%20X%20%3D%203%2F4%20%2A%202%20)
![3/4/2 = 1.5/4 = 3/8](https://tex.z-dn.net/?f=%203%2F4%2F2%20%3D%201.5%2F4%20%3D%203%2F8%20)
So X = 3/8!
Answer:
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In ΔABC is an oblique triangle with sides a,b and c , then asinA=bsinB=csinC . To use the Law of Sines you need to know either two angles and one side of the triangle (AAS or ASA) or two sides and an angle opposite one of them (SSA).