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masya89 [10]
4 years ago
12

DG¯¯¯¯¯¯ , EG¯¯¯¯¯ , and FG¯¯¯¯¯ are perpendicular bisectors of the sides of △ABC . BE=3 cm and GE=4 cm.

Mathematics
2 answers:
joja [24]4 years ago
8 0
The answer to your question is 5cm.
puteri [66]4 years ago
6 0

Answer:

your answer is 5.

Step-by-step explanation:

all the sides are the same because of the right angle signs; that means the lines are 90 degrees and are midway markers in this triangle. for example, the midway markers mean EC is 3 as well, and BEC is 6, since 3+3=6.

so since we know ge is 4, and we know be is 3, we know ad = be and dg = eg. find the hypotenuse of these two bad boys. a^2+b^2=c^2.

now plug in variables: 3^2+4^2=ag^2. 9+16=25. find the square root of the hypotenuse (because we need ag, not ag^2). your answer is five, and you're done. :)

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vlabodo [156]
\sqrt{6.1^2-4*-4.9*-0.8}  ≈ 4.64
8 0
3 years ago
Can you please solve and explain how
Karolina [17]

First, it would help to simplify each side more:

Left side: 36 + 3(4x - 9) = 36 + 12x - 27 = 12x + 9

Right side: c(2x + 1) + 25 = 2cx + c + 25

Write the simplified equation:

12x + 9 = 2cx + c + 25

Usually when there is no solution, the coefficients of the variable on both sides are the same, so we can make the coefficient if x on the right side into 12:

2cx >>> 12x

Then, c must equal 6 to make this true.

The answer is choice (C).

6 0
3 years ago
Read 2 more answers
the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu
Snowcat [4.5K]
It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}
\\
\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}
\\
\\=\frac{-42\pm \sqrt{1764}}{-19.6}
\\
\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}
\\
\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}
\\
\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
8 0
3 years ago
1/4 divided by 3 = ___
Yuki888 [10]

Answer:

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6 0
3 years ago
Read 2 more answers
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marta [7]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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