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4 years ago

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DG¯¯¯¯¯¯ , EG¯¯¯¯¯ , and FG¯¯¯¯¯ are perpendicular bisectors of the sides of △ABC . BE=3 cm and GE=4 cm.

2 answers:

joja [24]4 years ago

8 0

The answer to your question is 5cm.

puteri [66]4 years ago

6 0

Answer:

your answer is 5.

Step-by-step explanation:

all the sides are the same because of the right angle signs; that means the lines are 90 degrees and are midway markers in this triangle. for example, the midway markers mean EC is 3 as well, and BEC is 6, since 3+3=6.

so since we know ge is 4, and we know be is 3, we know ad = be and dg = eg. find the hypotenuse of these two bad boys. a^2+b^2=c^2.

now plug in variables: 3^2+4^2=ag^2. 9+16=25. find the square root of the hypotenuse (because we need ag, not ag^2). your answer is five, and you're done. :)

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LaTesha and Bernard are playing a game. Their scores for five games are shown in the table below. LaTesha’s and Bernard’s Scores

andre [41]

Answer:

The means differ by 1, but the ranges differ by 40.

Step-by-step explanation:

The mean for LaTesha's score is (92+45+67+36+80)/5= 64

The mean for Benards score is (63+68+62+69+53)/5= 63

The range for LaTeshas score is 92-36=56

The range for Benards score is 69-53=16

So, 64-63=1 and 56-16= 40

6 0

3 years ago

For males in a certain town, the systolic blood pressure is normally distributed with a mean of 110 and a standard deviation of

Blababa [14]

Answer: 95%

Step-by-step explanation:

6 0

3 years ago

Verna shipped three packages to chicago. If the packages weighed 12 1/2, 35 1/4, and 41 7/20 pounds, what was the total weight?

stiv31 [10]

Answer:

A

Step-by-step explanation:

1st package weighs $12\dfrac{1}{2}$ pounds;

2nd package weighs $35\dfrac{1}{4}$ pounds;

3rd package weighs $41\dfrac{7}{20}$ pounds;

First, add whole numbers:

$12+35+41=88$

Now add fractions:

$\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{7}{20}=\dfrac{10}{20}+\dfrac{5}{20}+\dfrac{7}{20}=\dfrac{10+5+7}{20}=\dfrac{22}{20}=\dfrac{11}{10}=1\dfrac{1}{10}$

So, the total weight is

$88+1\dfrac{1}{10}=89\dfrac{1}{10}\ pounds$

3 0

4 years ago

Casey boards a Ferris wheel at the 3-o'clock position and rides the Ferris wheel for multiple revolutions. The Ferris wheel rota

DochEvi [55]

Solution :

It is given that :

Casey boarded a Ferry wheel at position of 3 'o' clock.

The angular speed of the Ferry wheel = 5.6 radians per minute

The radius of the Ferry wheel = 50 feet

The height of the center wheel of the Ferry from the ground = 55 feet

Let the number of minutes be = t

a). The expression of the varying number of radians θ is given by :

After t minutes, θ = angle swept

θ = 5.6 t radians

b). Finding the height from the center of the wheel.

We know that : y = r sin θ

Given r = 50 feet

So, y = 50 sin (5.6 t) feet

Therefore, the height above the ground can be found by :

h = y + 55 (from ground)

h = 50 sin (5.6 t) + 55 feet

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3 years ago

Vedmedyk [2.9K]

Boop beep boop beep boop boop beep boop

8 0

3 years ago

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