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ivanzaharov [21]
3 years ago
14

What is the slope of a line perpendicular to y=4/3x+4

Mathematics
1 answer:
zheka24 [161]3 years ago
3 0
The answer is perpendicular = -4/3
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Please help me find the answer.
Sati [7]

Answer:

a = 16 and b = 2

Step-by-step explanation:

3 0
2 years ago
The sum of three consecutive integers is 53 more than the least of the integers. Find the integers. Really need the help!!
inn [45]

Answer:

25, 26, 27

Step-by-step explanation:

x+x+1+x+2=x+53

3x+3=x+53

2x=50

x=25

so x=25, x+1=26, x+2=27

3 0
3 years ago
Select the three equations that pass through the points (-4, -16) and (5,2).
dezoksy [38]

Answer:

The equation of the line is y-2 = 2(x - 5), that passes through points (-4, -16)\ and\ (5,2)

Step-by-step explanation:

Given points are (-4, -16)\ and\ (5,2)

We need to write the equation of the line that passes through these points

First, we will find slope of this line

m=\frac{y_2-y_1}{x_2-x_1}\\\\m=\frac{2-(-16)}{5-(-4)}\\\\m=\frac{2+16}{5+4}\\\\m=\frac{18}{9}=2

So, our slope is 2. Now, we will plug the point (5,2) in the equation below.

(y-y_1)=m(x-x_1)\\y-2=2(x-5)\\

So, the equation of the line is y-2 = 2(x - 5).

5 0
3 years ago
Read 2 more answers
Which of the following is equal to the fraction below?
Vesna [10]

In mathematics there is a rule of exponents where we can "distribute" the powers/exponents in the numerator and denominator of any expression. Therefore, given an expression as (\frac{a}{b})^n, the exponent n can be "distributed" as: (\frac{a}{b})^n= \frac{a^n}{b^n}.

In our case, the power, n=11; a=7 and b=4. Thus, the expression (\frac{7}{4})^{11}, can be written as \frac{7^{11}}{4^{11}}.

Thus, out of the given options, option A is the correct option.

6 0
3 years ago
Read 2 more answers
the point slope form of the equation of a line that passes through (8,4) and (0,2) is y-4=1/4(×-8) what is the slope intercept f
marissa [1.9K]

Answer:

\large\boxed{y=\dfrac{1}{4}x+2}

Step-by-step explanation:

The slope-intercept form of the equation of a line:

y=mx+b

m - slope

b - y-intercept → (0, b)

The point-slope form of the equation of a line:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point

We have the equation of a line:

y-4=\dfrac{1}{4}(x-8)\to m=\dfrac{1}{4}

and the point (0, 2) → b = 2.

Substitute:

y=\dfrac{1}{4}x+2

7 0
3 years ago
Read 2 more answers
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