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docker41 [41]
3 years ago
8

How do you solve capacity?​

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
5 0

Answer:

Cube and rectangle- length times with times height

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Megan and Kate decided to race their bikes. If Megan can ride at 12 mph and Kate can ride at 16 mph, how long until they are 1 1
Shkiper50 [21]
You would have to use an equation. The equation should be 12n+16n=1.5 When you found your answer, you should then use that decimal amount to "times" one hour to get the time. I am pretty sure that this is correct.
6 0
3 years ago
Moving the decimal point to the right 4 places in a number is the same as _____. multiplying by 10 -4 multiplying by 4 multiplyi
faltersainse [42]

Answer:

10^4

Step-by-step explanation:

lets say the number is 1.0 if you where to move the decimal to the right 4 place the number would then be 10,000.0. basically if it says 10^4 add 4 0's

7 0
3 years ago
Read 2 more answers
Can you guys help me with all the problems shown..
vladimir2022 [97]
4) 21
5) 36
6) 29.25

I used porpotions on all of these.
Sorry I don't remember the units.
4 0
4 years ago
Find f(t – 3) for f(x) = 4x^2 – 8x + 4.
Vladimir79 [104]

Answer:

<h2>A. 4t² - 32t + 64</h2>

Step-by-step explanation:

Instead of x put (t - 3) in the equation of the function f(x) = 4x² - 8x + 4:

f(t - 3) = 4(t - 3)² - 8(t - 3) + 4

<em>use (a - b)² = a² - 2ab + b² and the distributive property a(b + c) = ab + ac</em>

f(t - 3) = 4(t² - (2)(t)(3) + 3²) + (-8)(t) + (-8)(-3) + 4

f(t - 3) = 4(t² - 6t + 9) - 8t + 24 + 4

f(t - 3) = (4)(t²) + (4)(-6t) + (4)(9) - 8t + 28

f(t - 3) = 4t² - 24t + 36 - 8t + 28

f(t - 3) = 4t² + (-24t - 8t) + (36 + 28)

f(t - 3) = 4t² - 32t + 64

3 0
3 years ago
You draw two marbles from a bag containing 3 blue marbles,2 green marbles and 5 red marbles without replacement. what is the pro
lina2011 [118]
The probability of drawing a red marble then a green marble would be 1/9.
In the first draw, there is a total of 10 marbles to choose from, and choosing a red marbles' probability would be 5/10, or 1/2. However in the second draw, there are only 9 marbles to choose from since you have already taken out a marble. Choosing a green marble in the second draw's probability would be 2/9. Using the rule P(A and B) = P(A) • P(B), we can also apply it to this problem "P(choosing a red marble first and then choosing a green marble second)" = 1/2 • 2/9, which is equal to 2/18. If you simplify that, you get 1/9.
5 0
3 years ago
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