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vivado [14]
3 years ago
12

The minimum spanning tree of an undirected graph G exists if and only if G is connected. True or False?

Computers and Technology
1 answer:
zlopas [31]3 years ago
3 0

Answer: True

Explanation:

The definition of minimum spanning tree(MST) says that the graph must be connected and undirected to be considered for MST. It has (V-1) edges where V is the number of vertices. The minimum spanning tree is implemented using Kruskal's algorithm whereby it starts by considering the minimum weighted edge and covers all the edges upto (V-1) edges. So for MST it has to be connected

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Write a method transpose, that takes as argument a 2D array of integers, myTable, and returns the transpose of myTable. The tran
Gelneren [198K]

Answer:

The program to this question can be given as:

Program:

import java.util.*; //import package

public class Main //defining class

{

public static int[][] transpose(int[][] a1) //defining function transpose

{

int i,j; //define variables

int[][] transpose = new int[a1[0].length][a1.length]; //define variable transpose.

//loop for transpose matrix.

for(i = 0; i < a1.length; i++)  

{

for(j = 0; j < a1[i].length; j++)

{

transpose [j][i] = a1[i][j]; //hold value in transpose variable

}

}

return transpose ; //return transpose matrix.  

}

public static void main(String[] args) //main method.

{

int row,col,i,j; //defining variable.

Scanner obj = new Scanner(System.in); //creating Scanner class Object

System.out.print("Enter number of rows: ");//message

row = obj.nextInt(); //input rows form user.

System.out.print("Enter number of columns: ");//message

col = obj.nextInt(); //input columns form user.

int[][] a1 = new int[row][col]; //defining array.

System.out.println("Enter matrix"); //message

// loop for input array elements from user

for(i=0; i<a1.length;i++)  

{

for(j=0; j<a1[i].length;j++)  

{

a1[i][j]=obj.nextInt(); //input in array variable.

}

}

System.out.println("Matrix you insert :"); //message

// loop for display array.

for(i=0; i<a1.length;i++)  

{

for(j=0; j<a1[i].length;j++)  

{

System.out.print(a1[i][j]+" "); //print matrix

}

System.out.print("\n");

}

int[][] result = transpose(a1); //define result array variable that holds function value.

System.out.println("Transposed matrix is :");

//use loop for print Transpose matrix.

for(i = 0;i < result.length;i++)

{

for (j = 0; j < result[i].length;j++)

{

System.out.print(result[i][j] + " "); //print matrix

}

System.out.print("\n");

}

}

}

Output:

Enter number of rows: 2

Enter number of columns: 3

Enter matrix

2

3

4

9

8

7

Matrix you insert :

2 3 4  

9 8 7  

Transposed matrix is :

2 9  

3 8  

4 7  

Explanation:

The description of the above program can be given as:

  • In the above program firstly import a package, then declare a class that is "Main" inside a class defining a transpose() function this function returns a matrix in transpose form.
  • In the main class, we define a variable and matrix that is "row, col, i, j and a1[][]".  Then we Creating a scanner class object, which is used by row, col and a1[][] variables for user input.  
  • The row and col variables are used to declare matrix size and i, j variable is used in the loop for insert and display matrix.  
  • a1[][] matrix is used for input matrix elements and passes into transpose() function as an argument that returns a value that is held in the result variable. This is used as a loop for the print transpose matrix.

5 0
3 years ago
Number of byte required to store illumination
Rina8888 [55]
If we are talking about light that’s an whole different subject
5 0
3 years ago
legacy application that has hard-coded static IP addresses and is running on an EC2 instance, what is the best failover solution
AlladinOne [14]

Answer:

Elastic IP address

Explanation:

Elastic IP addresses are static, persistent public IP addresses which can be associated and disassociated with the instance, as required.

This will provide the best failover solution that will keep same IP address on a new instance.

6 0
4 years ago
Why is body language an important factor in a business meeting
slava [35]

The importance of the body language in business. Body language is a language without spoken words, it is called non verbal communication. We use it all the time in our social life and business life so it is all about gestures movements and expressions made by people to deliver a specific message to other people. Business meetings are all about making a good impression.

5 0
3 years ago
Ming's computer crashed suddenly the other day. Ming kept trying the solution that worked last few times it had crashed, even th
Nesterboy [21]

Answer:

A mental set is the correct answer of this question.

Explanation:

Ming's computer crashed abruptly the next day. Ming has continued to try the workaround the last couple of times it's crashed, though it's clear that it's not going to fix his computer now. The inability of Ming to overcome this issue is most likely due to a collection of mentalities.Because of his mental set he fails to solve the problem.

It means it is directly related to the mind set of the computer system the main objective of mental set in computer to solve the problem is mental set in computer is not crashed then computer system is not working.

3 0
3 years ago
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