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rewona [7]
3 years ago
8

Files and folders in UNIX can be removed using the

Computers and Technology
1 answer:
wel3 years ago
3 0

<em>Files and folders in UNIX can be removed using the</em>  <u><em>rm command.</em></u>

<em>The answer is B. rm command </em>

<em>Hope this helps :)</em>

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I have six nuts and six bolts. Exactly one nut goes with each bolt. The nuts are all different sizes, but it’s hard to compare t
juin [17]

Answer:

Explanation:

In order to arrange the corresponding nuts and bolts in order using quicksort algorithm, we need to first create two arrays , one for nuts and another for bolts namely nutsArr[6] and boltsArr[6]. Now, using one of the bolts as pivot, we can rearrange the nuts in the nuts array such that the nuts on left side of the element chosen (i.e, the ith element indexed as nutArr[i]) are smaller than the nut at ith position and nuts to the right side of nutsArr[i] are larger than the nut at position "I". We implement this strategy recursively to sort the nuts array. The reason that we need to use bolts for sorting nuts is that nuts are not comparable among themselves and bolts are not comparable among themselves(as mentioned in the question)

The pseudocode for the given problem goes as follows:

// method to quick sort the elements in the two arrays

quickSort(nutsArr[start...end], boltsArr[start...end]): if start < end: // choose a nut from nutsArr at random randElement = nutsArr[random(start, end+1)] // partition the boltsArr using the randElement random pivot pivot = partition(boltsArr[start...end], randElement) // partition nutsArr around the bolt at the pivot position partition(nutsArr[start...end], boltsArr[pivot]) // call quickSort by passing first partition quickSort(nutsArr[start...pivot-1], boltsArr[start...pivot-1]) // call quickSort by passing second partition quickSort(nutsArr[pivot+1...end], boltsArr[pivot+1...end])

// method to partition the array passed as parameter, it also takes pivot as parameter

partition(character array, integer start, integer end, character pivot)

{

       integer i = start;

loop from j = start to j < end

       {

check if array[j] < pivot

{

swap (array[i],array[j])

               increase i by 1;

           }

 else check if array[j] = pivot

{

               swap (array[end],array[j])

               decrease i by 1;

           }

       }

swap (array[i] , array[end])

       return partition index i;

}

7 0
3 years ago
Un comerciante de régimen código para comprar mercancías gravadas a un comerciante de régimen simplificado precio de venta al pú
Genrish500 [490]

Answer:

El valor sin impuestos de las mercancías era de $1.512.605.

Explanation:

Dado que un comerciante de régimen código para comprar mercancías gravadas a un comerciante de régimen simplificado pagó un precio de venta al público 1.800.000 incluido el IVA tarifa general (19%), para determinar el valor de las mercancías sin el impuesto incluido se debe realizar el siguiente cálculo:

1.19 = 1.800.000

1 = X

1.800.000 / 1.19 = X

1.512.605 = X

Por lo tanto, el valor sin impuestos de las mercancías era de $1.512.605.

5 0
3 years ago
Andrea wants to to install a new internet connection . she eants to use the fastest one she can find . what are the maximum spee
DaniilM [7]

A dial-up access connection supports a speed up to <u>5</u><u>6kbps</u>, whereas an ISDN line goes up to 1.9Mbps. A DSL connection can support a maximum of 20<u>mbps</u>. Internet access speed through cable TV is capable of up to 1000mbps.

Dial-up connection is by far the slowest of all known internet connections. The maximum speeds that can be supported by this connection are about 56Kbps. Use of this type of connection requires a separate phone line. In an ISDN type of connection, the maximum speeds depend on where in the world you are. The highest to have ever been recorded is an ISDN E1 line that has a combined data rate of 1.9 Mbit/s. Speeds transmitted through DSL are generally the same ones that are transmitted through cable internet and satellite connection. You can expect DSL speeds of 512Kbps to a max of 20Mbps. The cable internet is a broadband internet access and the highest bit rates of cable internet can go be up to 1GBPS which is equivalent to 1000Mbps.

6 0
3 years ago
Which of the following is not true about a list of lists
Thepotemich [5.8K]

Answer:

Where's the list??

3 0
3 years ago
Create a class named Horse that contains the following data fields: name - of type String color - of type String birthYear - of
kozerog [31]

Answer:

The program to this question can be given as:

Program:

class Horse   //define class Horse

{  

private String name;   //define variables.

private String color;  

private int birthYear;  

//define set method.

public void setName(String name)  

{  

this.name = name; //set value of name.

}

public void setColor(String color)  

{  

this.color = color; //set value of color.  

}  

public void setBirthYear(int birthYear)

{  

this.birthYear = birthYear;  //set value of birthYear

}  

//define get method.

public String getName()  

{  

return name;  //return name.

}  

public String getColor()

{  

return color;  //return color.

}  

public int getBirthYear()

{  

return birthYear;  //return birthYear.

}  

}

class RaceHorse extends Horse     //define class RaceHorse  

{

private String raceNum;            //define variable.

public void setRace(String raceNum)    //define set method.

{

 this.raceNum=raceNum;      //set value of raceNum.

}

public String getRace()

{

 return raceNum;   //return raceNum

}

}

public class Main      //define main class.

{

public static void main(String[] args) //define main method.

{

 Horse ob= new Horse();  //creating class objects.

 RaceHorse ob1 = new RaceHorse();

 ob.setName("XXX");       //calling function

 ob.setColor("BLACK");

 ob.setBirthYear(2008);

 ob1.setRace("Five hundred meter");

 //print return values.

       System.out.println("The name of the horse is " + ob.getName()+"." +"\n"+  

   "The horse's color is " + ob.getColor()+"."+"\n"+ "It was born in " + ob.getBirthYear() +  

   "."+"\n"+ ob.getName()+" has taken part in " + ob1.getRace() + " races.");

   

}

}

Output:

The name of the horse is XXX.

The horse's color is BLACK.

It was born in 2008.

XXX has taken part in Five hundred meter races.

Explanation:

In the above program firstly we declare the class that is Horse in this class we define a variable that name is already given in the question which are name, color, and birthYear. In these variables are name and color datatype is string and the birthYear datatype is an integer because it stores the number. Then we use the get and set function in the get function we return all variable value. and in the set function, we set the values of the variable by this keyword. Then we declare another class that is RaceHorse this class inherit Horse class. In the RaceHorse class, we define a variable that is raceNum that's data type is a string in this class we also used the get and set function. Then we declare the main class in the main class we define the main method in the main method we create the above class object and call the set and get function and print the values of the function.

6 0
3 years ago
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