i believe the answer is hours.
Answer:
A
Step-by-step explanation:
the "-" sign simply turns everything upside-down. what was above the x-axis is now below it. and vice versa. hence, a reflection over the x-axis.
the "+6" moves then everything up by 6 units. which is a vertical shift up by 6 units.
<span>Let's try to solve the equation:
1/x + 1/(x)² = 2
Kelly says that it is not possible because there are the variable x and x² in the denominators. Kelly is correct in that there is a value of x that makes the denominator zero. In this case, x = 0 makes the denominator of 1/x zero and also makes the denominator of 1/x² = 0.
</span>But, we want to look for values of x that will make the whole equation true, not the values of x that make the denominators zero. 1/x + 1/(x)² = 2
(x +1)/(x)² = 2
Multiply through by x² with the proviso that x is not 0.
Then,
(x + 1) = 2x²
At this point, we are looking for solutions to (x + 1) = 2x² which is related to but not identical to the original equation. So, we will have to check any answers we get to
(x + 1) = 2x² against the original problem: 1/x + 1/(x)² = 2
Answer:
3
x
+
2
y
+
z/
x
+
y
+
z
, x
=
2
, y
=
3
, z
=
1
tan
(
x
)
, x
=
−
π
cot
(
3
x
)
, x
=
2
π
/3
Step-by-step explanation:
Answer:
9
√
2
Step-by-step explanation:
1. Rewrite 162 as
⋅2
2. factor 81 out of 162
![\sqrt{81 (2)}](https://tex.z-dn.net/?f=%5Csqrt%7B81%20%282%29%7D)
3. Rewrite 81 as ![9^{2}](https://tex.z-dn.net/?f=9%5E%7B2%7D)
![\sqrt{9^{2}.2 }](https://tex.z-dn.net/?f=%5Csqrt%7B9%5E%7B2%7D.2%20%7D)
4. Pull the terms from under the radical
![\sqrt[9]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B9%5D%7B2%7D)
I hope this helps :)