Charlene has four<br> -0.5 cards. What is the total value of her<br> cards?

USPshnik [31]

$TQ = \sqrt{ {PQ}^{2} - {PT}^{2} } = \sqrt{{20}^{2} - {16}^{2} } = \sqrt{144} = 12\: mm \\ Area:16 \times 12 \times 2 = 384\: {mm}^{2}$

3 0

3 years ago

There are 4 colas, 1 ginger, 7 root beers, and 6 cherry sodas in a cooler. What are the odds of choosing a ginger ale? Give your

andreyandreev [35.5K]

Answer:

Step-by-step explanation:

the odds of choosing a ginger ale is 1/21

7 0

4 years ago

Read 2 more answers

A rancher plans to make 4 identical and adjacent rectangular pens against a barn (see figure below), each with an area of 100 m^

Tasya [4]

Answer:

10 by 10 meters

Step-by-step explanation:

In calculus terms, you can use the formula for the perimeter which is 2l + 2w, and the area l × w.

Then since the area is 100

l × w = 100. So w = 100/l

Then substitute this into the perimeter formula.

w = 100/l → 2l + 2(w) = 2l + 2(100/l) = 2l + 200/l.

Then take the derivative d/dx [take the derivative of a quantity with respect to x], by using a simpler method known as the power rule:

d/dx[x^n] = nx^n-1

so p = 2l + 200/l becomes p' = 2 - 200/l^2

Since the derivative of a constant is 0, to solve for l, set p' to 0

0 = 2 - 200/l^2 → -200/l^2 = -2 → 200/l^2 = 2 → 2l^2 = 200 → l^2 = 100 → l = √100, l = 10.

Now that we know the length is 10, We can substitute the length in the original equation to find the width.

l = 10 → w = 100/l → w = 100/10, w = 10.

Therefore the perimeter of each rectangular pen is 40, with a length of 10 and width of 10.

If you want to do this algebraicly, there are more steps involved

7 0

3 years ago

PLEASE HELP ASAP!!!!! i’ll mark brainlest

hoa [83]

Answer:

It would be hundreds

Step-by-step explanation:

I hope it is right :I

4 0

3 years ago

You know that y is a normally distributed variable with a variance of 9. You do not know its mean. You collect some data. For ea

Dima020 [189]

Answer:

a)

CI = ( 1.2718, 8.0614 )

Since value 2 is contained within Confidence Interval, fail to Reject H₀

b)

CI = ( -2.2296, 3.0296 )

Since value 2 is contained within Confidence Interval, fail to Reject H₀

c)

CI = ( 0.2962, 4.4538 )

Since value 2 is contained within Confidence Interval, fail to Reject H₀

Step-by-step explanation:

Given that;

Variance σ² = 9

so standard deviation σ = √9 = 3

with 95% confidence interval in each case. thus, The Z value for 95% confidence is Z = 1.96

Null Hypotheses H₀ : μ = 2

Now

a) (8,1,5)

sample mean x" = (8+1+5) / 3 = 14/3 = 4.6666

n = 3

Confidence Interval CI = x" ± ( z × σ/√n )

CI = 4.6666 ± ( 1.96 × 3/√3 )

CI = 4.6666 ± 3.3948

so CI = ( 1.2718, 8.0614 )

Since value 2 is contained within Confidence Interval, fail to Reject H₀

b) (8,1,5,-4,-8)

sample mean X" = (8 +1 + 5 - 4 - 8) / 5 = 2 / 5 = 0.4

n = 5

Confidence Interval CI = x" ± ( z × σ/√n )

CI = 0.4 ± ( 1.96 × 3/√5 )

CI = 0.4 ± 2.6296

so CI = ( -2.2296, 3.0296 )

Since value 2 is contained within Confidence Interval, fail to Reject H₀

c) (8,1,5,-4,-8,4,8,5)

sample mean x" = (8 + 1 + 5 - 4 - 8 + 4 + 8 + 5) / 8 = 19 / 8 = 2.375

n = 8

Confidence Interval CI = x" ± ( z × σ/√n )

CI = 2.375 ± ( 1.96 × 3/√8 )

CI = 2.375 ± 2.0788

so CI = ( 0.2962, 4.4538 )

Since value 2 is contained within Confidence Interval, fail to Reject H₀

8 0

3 years ago

Charlene has four -0.5 cards. What is the total value of her cards?