Answer: 0
Step-by-step explanation:
I started by labeling the right angle (Angle C) 90º. Next, I wrote down everything in one equation.
2x + 90 + 3x - 20 = 180º (180 degrees in a triangle)
Next, I add 20 on both sides.
2x + 90 + 3x = 200º
I combine like terms (2x and 3x)
5x + 90 = 200º
I subtract 90 from both sides.
5x = 110º
Divide 110 by 5 to get x.
x = 22
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For problem two, I label all the angles I know.
49º + 80º + r = 180º
I add 80 and 49.
129º + r = 180º
I subtract 180 and 129 and get 51º, which is your angle for R.
For angle X, you know that angle R plus angle X equals half of a circle, which is 180º
We know from before that 129º is 180º without R, so X is 129º
I hope this helps! Let me know if I'm wrong!
The answer is w⁻²/v⁻².
v/w raised to the second power is (v/w)²
(v/w)² = v²/w²
Since xᵃ = 1/x⁻ᵃ, then v²/w² = 1/v⁻²w²
Since 1/xᵃ = x⁻ᵃ, then 1/v⁻²w² = w⁻²/v⁻²
Answer:
4.9%
Step-by-step explanation:
This question is incomplete. However; it can be found on search engines. The complete question is as follows :
An ice chest contains cans of six apple juice, eight cans of grape juice, four cans of orange juice, and two cans of mango juice. Suppose that you reach into the container and randomly select three cans in succession. Find the probability of selecting three cans of grape juice.
Solution :
In an ice chest there are different cans of juice. Among them
Number of cans of apple juice = 6
Number of cans of grape juice = 8
Number of cans of orange juice = 4
Number of cans of mango juice = 2
Total number of cans of juice = 6 + 8 + 4 + 2 = 20
Let A, B and C are the event of selecting of three cans. The events A, B and C are dependent.
Probability of selecting three cans of juice
P = 
P (A) = 
P (B) = 
P (B) = 
P =
×
× 
= 
= 0.049 or 4.9%
Probability of selecting three cans of grape juice is 4.9%
Well. You start with two rabbits, and it triples every month, so:
0 months: 2 rabbits.
1 month: 2*3 = 6 rabbits.
2 months: 6*3 = 18 rabbits.
3 months: 18*3 = 54 rabbits.