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viktelen [127]
3 years ago
14

What is 5.008 as a fraction or mixed number

Mathematics
2 answers:
dlinn [17]3 years ago
6 0

5.008

As a fraction:            5008 / 1000

As a mixed number:  5 and 8/1000

tino4ka555 [31]3 years ago
5 0
The fraction would be 5 8/1000
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There are 21 more green crayons than blue crayons. There are 14 blue crayons. How many green crayons are there?
dimaraw [331]

Answer:

35 green crayons

Step-by-step explanation:

g is number of green crayons

b is number of blue crayons

g = b + 21

plug in 14 for b:

g = 14 + 21

g = 35

35 green crayons

3 0
3 years ago
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John invested $4,500 at 5.5% annual simple interest. His maturity value of his investment was $5,545. How long did John invest t
mart [117]

John invested the money at simple interest for 4.22 years.

We have,

Invested amount = $ 4500

Rate of interest = 5.5 %

Time = t years

Maturity value = $ 5545

So,

Total interest earned =  $ 5545 - $ 4500 = $ 1045

And,

Simple interest = (Principal × Rate × Time ) / 100

So, Using the mentioned formula,

1045 = ( 4500 × 5.5 × t ) /100

1045 = 45 × 5.5 × t

⇒

t = (1045) / (45 × 5.5)

⇒ t = 4.22 years

Therefore, John invested the money at simple interest for 4.22 years.

Learn more about simple interest here:

brainly.com/question/22621039

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6 0
2 years ago
Round 101 to the nearest ten
Lesechka [4]
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7 0
3 years ago
12 is what percent of 19​
VikaD [51]

Answer:

63%

Step-by-step explanation:

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7 0
3 years ago
Examine the following steps. Which do you think you might use to prove the identity Tangent (x) = StartFraction tangent (x) + ta
Over [174]

Answer:

The correct options are;

1) Write tan(x + y) as sin(x + y) over cos(x + y)

2) Use the sum identity for sine to rewrite the numerator

3) Use the sum identity for cosine to rewrite the denominator

4) Divide both the numerator and denominator by cos(x)·cos(y)

5) Simplify fractions by dividing out common factors or using the tangent quotient identity

Step-by-step explanation:

Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;

tan(x + y) = sin(x + y)/(cos(x + y))

sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

6 0
3 years ago
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