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3 years ago

8. A blueprint of a house has a scale of 1 in: 6 ft. If a bedroom has a width

Mathematics

1 answer:

natulia [17]3 years ago

6 0

A blueprint of a house has a scale of 1 in: 6 ft. If a bedroom has a width

of 2 in on the blueprint, what is the actual width of the bedroom?

So 1 inch on the blue print = 6 feet irl (in real life)

So 2 inch on the blue print = 6*2 = 12 feet irl

So the actual width of the bedroom is 12 feet.

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How would you multiply. ? 3.5 2 ca D 52 3.5

hram777 [196]

Answer:

1274Dac

Step-by-step explanation:

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2 years ago

What is the difference of the rational expressions below?

Verdich [7]

Answer:

work is shown and pictured

7 0

2 years ago

Use the diagram to answer the questions

IRISSAK [1]

Answer:

1. B. BD

2. C. 15

3. A. 2

Step-by-step explanation:

1. From the figure,

∠DAB = ∠DAC

Therefore, BD is the bisector of ∠ABC.

2. From the figure, IG = GH

3x = 5x - 10

10 = 5x - 3x

2x = 10

x = 5

So, GH = 5x - 10

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= 15

Therefore, GH = 15.

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∠DAB = ∠DAC

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8 0

3 years ago

Solve the quadratic equation<br> give your answer to 2 decimal places<br> : 3x^2+x-5=0

Dima020 [189]

Given:

The quadratic equation is:

$3x^2+x-5=0$

To find:

The solution for the given equation rounded to 2 decimal places.

Solution:

Quadratic formula: If a quadratic equation is $ax^2+bx+c=0$ , then:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

We have,

$3x^2+x-5=0$

Here, $a=3,b=1,c=-5$ . Using the quadratic formula, we get

$x=\dfrac{-1\pm \sqrt{1^2-4(3)(-5)}}{2(3)}$

$x=\dfrac{-1\pm \sqrt{1+60}}{6}$

$x=\dfrac{-1\pm \sqrt{61}}{6}$

$x=\dfrac{-1\pm 7.81025}{6}$

Now,

$x=\dfrac{-1+7.81025}{6}$

$x=1.13504167$

$x\approx 1.14$

And

$x=\dfrac{-1-7.81025}{6}$

$x=-1.468375$

$x\approx -1.47$

Therefore, the required solutions are 1.14 and -1.47.

3 0

2 years ago

Find x so that the two points are on the line with the given slope (1,-1) and (x,7): undefined

Annette [7]

Value of x for which the two points are on the line with the given slope (1,-1) and (x,7): undefined is $x=1$ .

<u>Step-by-step explanation:</u>

Here we have to Find x so that the two points are on the line with the given slope (1,-1) and (x,7): undefined . Let's find out:

We know that for any two points given as $P(x_1,y_1),Q(x_2,Y_2)$ slope of line is determined by :

⇒ $Slope = \frac{y_2-y_1}{x_2-x_1}$

According to question we have two points as $P(1,-1),Q(x,7)$ ∴

⇒ $Slope = \frac{y_2-y_1}{x_2-x_1}$

⇒ $Slope = \frac{7-(-1)}{x-1}$

But slope is undefined which is only possible when denominator is zero i.e.

⇒ $x-1=0$

⇒ $x=1$

Therefore , Value of x for which the two points are on the line with the given slope (1,-1) and (x,7): undefined is $x=1$ .

7 0

3 years ago