Could someone please help me with this problem and possibly explain if you can? (Will give up brainiest answer if correct, if po
ssible)
1 answer:
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7)
Given the line
We know that the slope-intercept form of the line equation is
here
m is the slope and b is the intercept
Thus, the slope = -1
We know that the parallel lines have the same. Thus, the slope of the parallel line is: -1
Using point-slope of the line equation
substituting the values m = -1 and the point (4, 0)
Writing in the slope-intercept form
Thus, the slope-intercept form of the equation of the line equation parallel to y=-x+ 2 will be:
8)
<em>Note: </em><em>Your line is a little bit unclear. But, I am assuming the</em>
<em>ine is: </em>y = -x-1
<em />
Given the assumed line
y = -x-1
We know that the slope-intercept form of the line equation is
here
m is the slope and b is the intercept
Thus, the slope = m = -1
We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:
slope = m = -1
perpendicular slope = – 1/m = -1/-1 = 1
Using point-slope of the line equation
substituting the values m = 1 and the point (4, 3)
Writing in the slope-intercept form
y-3 = x-4
y = x-4+3
y = x - 1
Thus, the slope-intercept form of the equation of the line equation perpendicular to y = -x-1 will be:
- y = x - 1