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artcher [175]
3 years ago
10

Which of the following class definitions is correct in Java?(i)public class Student{private String name;private double gpa;priva

te int id;public void Student(){name = "";gpa = 0;id = 0;}public void Student(String s, double g, int i){set(s, g, i);}public void set(String s, double g, int i){name = s;gpa = g;id = i;}public void print(){System.out.println(name + " " + id + " " + gpa);}}(ii)public class Student{private String name;private double gpa;private int id;public Student(){name = "";gpa = 0;id = 0;}public Student(String s, double g, int i){set(s, g, i);}public void set(String s, double g, int i){name = s;gpa = g;id = i;}public void print(){System.out.println(name + " " + id + " " + gpa);}}1. Both (i) and (ii)2. None of these3. Only (ii)4. Only (i)
Computers and Technology
1 answer:
Soloha48 [4]3 years ago
4 0

Answer:

The answer is "Option 3".

Explanation:

In the given question the code (ii) is correct because in the class definition class "Student" defines a constructor that does not use any return type. and code (i) class definition the class "Student" defines a constructor that uses return type void which is not allowed in the constructor. and other options are not correct that can be described as follows:

  • In option 1, only code (ii) is correct.
  • In option 2, code (ii) is correct that's why it is not correct.
  • In option 4, it is not correct, because it uses void return type.

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What are the first and the last physical memory addressesaccessible using
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Answer

For First physical memory address,we add 00000 in segment values.

For Last physical memory address,we add 0FFFF in segment values.

<u>NOTE</u>-For addition of hexadecimal numbers ,you first have to convert it into binary then add them,after this convert back it in hexadecimal.

a)1000

For First physical memory address, we add 00000 in segment value

We add 0 at the least significant bit while calculating.

          1000<u>0</u> +00000 = 1000<u>0</u> (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           1000<u>0</u> +0FFFF =1FFFF    (from note)

b)0FFF

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

     0FFF<u>0</u> +00000=0FFF0 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           0FFF<u>0</u> +0FFFF =1FFEF (from note)

c)0001

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

     0001<u>0</u> +00000=00010 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           0001<u>0</u> +0FFFF =1000F (from note)

d) E000

For First physical memory address,we add 00000 in segment value

 We add 0 at the least significant bit while calculating.

    E000<u>0</u> +00000=E0000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           E000<u>0</u> +0FFFF =EFFFF (from note)

e) 1002

For First physical memory address,we add 00000 in segment value

 We add 0 at the least significant bit while calculating.

    1002<u>0</u> +00000=10020  (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           1002<u>0</u> +0FFFF =2001F (from note)

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