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Daniel [21]
3 years ago
13

Find the number a such that the line x = a bisects the area under the curve y = 1/x2 for 1 ≤ x ≤ 4. 8 5​ (b) find the number b s

uch that the line y = b bisects the area in part (a).
Mathematics
1 answer:
IceJOKER [234]3 years ago
3 0

a. We're looking for a such that

\displaystyle\int_1^a\frac{\mathrm dx}{x^2}=\int_a^4\frac{\mathrm dx}{x^2}

-\dfrac1x\bigg|_{x=1}^{x=a}=-\dfrac1x\bigg|_{x=a}^{x=4}

1-\dfrac1a=\dfrac1a-\dfrac14

\dfrac54=\dfrac2a\implies\boxed{a=\dfrac85}

b. Integrating with respect to y will make things easier.

y=\dfrac1{x^2}\implies x=\dfrac1{\sqrt y}

(where we take the positive square root because we know x>0)

Now we want to find b such that

\displaystyle\int_0^b\frac{\mathrm dy}{\sqrt y}=\int_b^1\frac{\mathrm dy}{\sqrt y}

2\sqrt y\bigg|_{y=0}^{y=b}=2\sqrt y\bigg|_{y=b}^{b=1}

2\sqrt b=2-2\sqrt b

4\sqrt b=2\implies\boxed{b=\dfrac14}

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Determine whether each number is a solution of the given inequality 2m - 4 > 10
sladkih [1.3K]

Answer:

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Step-by-step explanation:

5 0
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5/8(x-1/3)=5/12 can someone help me figure out what x is?
eimsori [14]
Solve for x:(5 (x - 1/3))/(8) = 5/12
Put each term in x - 1/3 over the common denominator 3: x - 1/3 = (3 x)/3 - 1/3:(5 (3 x)/3 - 1/3)/(8) = 5/12
(3 x)/3 - 1/3 = (3 x - 1)/3:(5 (3 x - 1)/3)/(8) = 5/12
3×8 = 24:(5 (3 x - 1))/24 = 5/12
Multiply both sides of (5 (3 x - 1))/24 = 5/12 by 24/5:(24×5 (3 x - 1))/(5×24) = (24×5)/(5×12)
(24×5)/(5×12) = (24×5)/(5×12):(24×5 (3 x - 1))/(5×24) = (24×5)/(5×12)
(24×5 (3 x - 1))/(5×24) = (5×24)/(5×24)×(3 x - 1) = 3 x - 1:3 x - 1 = (24×5)/(5×12)
(24×5)/(5×12) = 5/5×24/12 = 24/12:3 x - 1 = 24/12
The gcd of 24 and 12 is 12, so 24/12 = (12×2)/(12×1) = 12/12×2 = 2:3 x - 1 = 2
Add 1 to both sides:3 x + (1 - 1) = 1 + 2
1 - 1 = 0:3 x = 2 + 1
2 + 1 = 3:3 x = 3
Divide both sides of 3 x = 3 by 3:(3 x)/3 = 3/3
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3 0
3 years ago
Need help !!!!!!!!!!!!!!!!!!!!!!!
stich3 [128]
Answer:  " m∠SRW = 95 ° " .
________________________________________________

Since m∠TRV = 95° ; 

and:  ∠TRV and ∠SRW are vertical angles; 

and:  we are given:  " m∠TRV = 95° " ; 

and:  vertical angles are congruent; 

So, m∠TRV = m∠SRW = 95°  .
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4 0
3 years ago
The taxi fare in a city is as follows: For the first kilometer, the
Ksju [112]

Answer:

The linear equation is y = 6 x + 9

The graph is attached down

Step-by-step explanation:

The given information:

The cost of 1st km is 9 Rs

The cost of every kilometer after the first is 6 Rs

x represents the number of km

y represents the total cost of x km

The form of the linear equation is

y = m x + b, where

  • m is the slope of the line (rate of change)
  • b is the y-intercept (initial value)

From the given information above

m = 6 Rs/km

b = 9 Rs

Substitute them in the form of the equation

y = 6 x + 9

The graph:

3 0
3 years ago
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