Jack and Jil, a boy, and a female are going as tons as filling the bucket with water. After filling it up, they begin mountain climbing. As they climb down, Jack all of sudden loses his footing and slips. As a give-up end result, he hurts himself and spills all of the water and Jill too tumbled after him.
Jack and Jill of the USA, Inc. is a membership corporation of moms with kids a while 2-19, dedicated to nurturing the destiny of African-American leaders by strengthening kids through management improvement, volunteer service, philanthropic giving, and civic duty.
Principal concern subjects in “Jack and Jill”: adventure and heroism are the fundamental topics of this poem. The poem presents youngsters with an acting domestic chore: getting water properly. Jack receives injured but he fast recovers.
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Answer:
it telling us we need pretty lies
Explanation:
After reading both excerpts from the novel "Strange Case of Dr. Jekyll and Mr. Hyde," we can say that Dr. Jekyll, in excerpt 2, is:
B. Concerned.
<h3>What is said in excerpt 2?</h3>
- In the second excerpt, Dr. Jekyll expresses his concerns over the fact that his alter-ego, Mr. Hyde, seems to be incorporating his normal self.
- Mr. Hyde represents the repressed side of Dr. Jekyll, his flaws and impulses. Jekyll fears that his normal self might disappear, and only Mr. Hyde will remain.
The two excerpts are the following:
Excerpt 1:
I had but to drink the cup, to doff at once the body of the noted professor, and to assume, like a thick cloak, that of Edward Hyde. I smiled at the notion; it seemed to me at the time to be humourous; and I made my preparations with the most studious care.
Excerpt 2:
Now, however, and in the light of that morning's accident, I was led to remark that whereas, in the beginning, the difficulty had been to throw off the body of Jekyll, it had of late gradually but decidedly transferred itself to the other side. All things therefore seemed to point to this; that I was slowly losing hold of my original and better self, and becoming slowly incorporated with my second and worse.
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Entries are listed in alphabetical order is the answer
Answer:
In Celcius your answer is,
-182.944444
And In Kelvin your answer is,
90.205556
Explanation:
For CELCIUS
Take the °F temperature and subtract 32.
Multiply this number by 5.
Divide this number by 9 to obtain your answer in °C.
The formula to convert °F to °C is:
<em>T(°C) = (T(°F) - 32) × 5/9</em>
For KELVIN,
To convert Kelvin into Fahrenheit, the formula is:
<em>(K − 273.15) × 9/5 + 32 = °F. </em>
