Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
<-7,-3>
Step-by-step explanation:
To write RS in component form we need to know how far to move over horizontally and then how many to move vertically.
Since horizontal movement is the x values, we subtract the x values of R and S first.
0 - 7 = -7
Since vertical movement is in the y values we subtract those next.
5 - 8 = -3
So written in component form we have <-7,-3>
9514 1404 393
Answer:
30 small chairs and 24 large chairs
Step-by-step explanation:
Let x and y represent the numbers of small chairs and large chairs built in a day. Then the relations for using available time are ...
20x +50y = 30×60
60x +90y = 66×60
Removing common factors, these can be written in standard form as ...
2x +5y = 180
2x +3y = 132
Subtracting the second equation from the first gives ...
2y = 48
y = 24 . . . . . divide by 2
Using the first equation to find x, we have ...
2x +5(24) = 180
2x = 60 . . . . . . . . . . subtract 120
x = 30 . . . . . . . . divide by 2
The company can build 30 small chairs and 24 large chairs in a day.
Answer:
The leghts of AB is 9 because both of the triangles are symmetrical. But also, this is a Equilateral triangle, which means that both of the sides are the same lengths (AB=AC)
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
Find out more on equation at: brainly.com/question/2972832
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