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mezya [45]
3 years ago
13

dave and his sister picked out two pumpkin at the pumpkin patch. the pumpkins cost $0.47 per pound. david's pumpkin weighed 13.2

4 pounds and his sister's pumpkin weighed 10.6 pounds. how much did they pay for both pumpkins?
Mathematics
2 answers:
pickupchik [31]3 years ago
6 0
David's pumpkin cost $8.22
His sister's pumpkin cost $4.98
They paid $13.20
Ulleksa [173]3 years ago
6 0

Answer: They paid $11.20 for both pumpkins.

Step-by-step explanation:

Hi, to answer this question, first, we have to sum both pumpkins’ weight.

  • Total weight: 13.24 + 10.6 = 23.84 pounds

Finally, to calculate the cost of both pumpkins, we have to multiply the cost per pound ($0.47) by the total weight obtained.

Mathematically speaking:

  • 23.84 x 0.47 = $11.20  

They paid $11.20 for both pumpkins.

Feel free to ask for more if needed or if you did not understand something.

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Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.
Mice21 [21]

Answer:

<em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

Step-by-step explanation:

Making factors of 8y^{6}+ 144y^{5}+ 640y^{4}

Taking 8y^{4} common:

\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)

Using <em>factorization</em> method:

\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times  4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)

Now, Making factors of 2y^{4} + 40y^{3} + 200y^{2}

Taking 2y^{2} common:

\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)

Using <em>factorization</em> method:

\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10)        ............ (2)

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is 2y^{2} (y+ 10).

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

HCF \times LCM = p \times q

Using equations <em>(1)</em> and <em>(2)</em>: \Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)

Hence, <em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

5 0
2 years ago
Is this right please help meh
Mama L [17]
Yes you are correct very nice job!
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