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Olenka [21]
3 years ago
5

Why are non-engineered or owner-built structures more vulnerable to hazards?

Biology
1 answer:
Bond [772]3 years ago
8 0

Answer:

Non-engineered/owner-build structures are more vulnerable because they can be poorly built. Without proper knowledge to build the right structure, the structure is more at risk of abnormalities or destruction from hazards such as rain, hail, strong winds, and debris.

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A tall pea plant (TT) is crossbred with a short pea plant (tt). The Punnett square below shows the separated alleles for two pea
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Hi there! 

Using the image below, you can see that all of the boxes are Tt, or heterozygous. Therefore, 1 = Tt, 2 = Tt, 3 = Tt, and 4 = Tt.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

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In most cells, there are more ______ molecules inside the cell and more sodium molecules outside the cell.
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it as more organic molecules inside

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What features of Therapsids suggest the group was transitional to reptiles and mammals?
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While alive, an organism absorbs (radioactive) carbon 14 at such a rate that the proportion of carbon 14 in the organism remains
Inga [223]

Answer:

The person has been dead for approximately 15,300 years

Explanation:

<u>Available data</u>:

  • The half-life of carbon 14 is 5,600 years
  • The human skeleton level of carbon 14 is 15% that of a living human

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

  • C14 T₀ ⇒ Amount of carbon in a living body at time 0 = 100%
  • C14T₁ ⇒ Amount of carbon in the dead body at time 1 = 15%
  • λ ⇒ radioactive decay constant = (Ln2)/T₀,₅
  • T₀,₅ ⇒ The half-life of carbon 14 = 5600 years
  • T₀ = 0
  • T₁ = ???

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5600

λ = 0.000123

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (15%/100%) = Ln 0.15 = - 1.89

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 1.89 = - 0.000123 x T₁

T₁ = - 1.89 / - 0.000123

T₁ = 15,365 years

The person has been dead for approximately 15,300 years

4 0
3 years ago
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