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3 years ago

Find the length of the hypotenuse of an isosceles right triangle whose legs are 1 unit in length.

Mathematics

2 answers:

vredina [299]3 years ago

7 0

Use the equation a2+b2=c2 the 2 is an exponent. the a and b are the side lengths. so plug everything in and you get 1)2+1)2=c2 and your answer would get you to 2=c2 then square root 2 or your answer would be 2 with the square root sign

stiks02 [169]3 years ago

6 0

check the picture below

and isosceles triangle, has two equal sides, thus, sides "a" and "b" for the triangle to be an isosceles, have to be equal

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Tim drove 217 miles in 3.5 hours. Emily drove 244 miles in 4 hours. Who drove faster?

Naya [18.7K]

Answer:

Tim

Step-by-step explanation:

Tim drove 62 miles per hour you get this by dividing 217 by 3.5 and then you divide Emily's. 244/4 and you get 61

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2 years ago

which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

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3 years ago

Multiply and simplify the product. –12i × 3i Select the product. 36 -36 36i -36i

bazaltina [42]

Answer:

Step-by-step explanation:

–12i × 3i

Multiply the numbers

-12*3 = -36

Multiply the imaginary number

i*i= i^2

We know i^2 = -1

-36 * -1 = 36

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Vlada [557]

Answer:

Step-by-step explanation:

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2 years ago