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Elis [28]
2 years ago
11

Pls help what is AC!!

Mathematics
2 answers:
PolarNik [594]2 years ago
6 0

Answer:

2.87

Step-by-step explanation:

Sinθ= P/H

Sin35°=AC/AB=AC/5

AC=5 Sin36°

AC=5×0.573

AC=2.865

≈ 2.87

Hope it helps! :)

Ivenika [448]2 years ago
3 0
I really think 90°, it looks like a 90° angle so i hope this is correct if not im very sorry!
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6 x 10 5 is how many times the value of 3 x 10 (Hint: Write your answer in standard form.)​
JulijaS [17]

Answer:

0.000036

Explanation:

When multiplying a number by 10 to the power of a positive exponent (e.g.  

10

3

), move the decimal in the number that many spaces to the right (e.g.  

4.5

⋅

10

3

=

4500

).

When multiplying a number by 10 to the power of a negative exponent (e.g.  

10

−

4

), move the decimal in the number (the absolute value of) that many spaces to the left (e.g.  

4.5

⋅

10

−

4

=

0.00045

).

For  

3.6

⋅

10

−

5

, move the decimal five spaces to the left:

0.000036

Step-by-step explanation:

5 0
3 years ago
Sarah calculates that she spends 15% of a school day and science class if she spends 75 minutes and science how many minutes doe
Monica [59]
.15x = 75 Divide both sides by .15 you get 500 minutes
4 0
3 years ago
15x+98=105 What is the value of x and please show your work. :) ​
Yuliya22 [10]

Answer:

15x+98=105

      -98    -98

15x=7

/15    /15

x=7/15

Step-by-step explanation:

x=7/15

4 0
3 years ago
I need help with this
Lady bird [3.3K]
I believe the answer to this is "If they babysit for 5 hours, Jayna will earn more" because Hannah charages 7$ an hour and Jayna charges 10$ an hour so Jayna will have more money than Hannah in five hours. 
4 0
3 years ago
Suppose a cold beer at 40°F is placed into a warm room at 70°F. Suppose 10 minutes later, the temperature of the beer is 48°F. U
Yuri [45]

Answer:

69.92°F

Step-by-step explanation:

Given:

Initial temperature ( i.e at time, t = 0) = 40°F

Temperature of the room = 70°F

Temperature after 10 minutes ( i.e at time t = 10 ) = 48°F

Now, from Newton's law of cooling

T'(t) = k(A - T(t))

T(t) temperature after time t

T'(t) = \frac{\textup{dT}}{\textup{dt}}

here, A is the room temperature

thus,

\frac{\textup{dT}}{\textup{dt}}  = k(70 - T)

or

\frac{\textup{dT}}{\textup{70-T}} = kdt

on solving the differential equation, we get

T = 70-C^{-kt} ............(1)

Now from the boundary conditions,

 i.e at time, t = 0; T = 40°F

we get,

40 = 70-C^{-k\times0}

or

C = 30

and,

at time, t = 10; T = 48°F

thus,

48 = 70-30^{-k\times10}

or

k = \frac{\textup{-1}}{\textup{10}}ln\frac{11}{15}

or

k = 0.03

Therefore,

for t = 25

from 1 we have

T = 70-30^{-0.03\times25}

or

T = 70 - 0.0780

or

T = 69.92°F

3 0
3 years ago
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