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Naddik [55]
2 years ago
7

9. Wade has 126 inches of 1-inch wide bias tape for a border

Mathematics
1 answer:
viktelen [127]2 years ago
6 0

Answer:

Let 'x' represent the width.

2*48 + 2x = 126

x = 15 in

The maximum width could be 15 inches.

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What is x*x=15? (Basically make an equation that equals up to 15.)
rodikova [14]

Answer:

\displaystyle \sqrt{15} = x

Step-by-step explanation:

Be VERY careful. When it write out the equation that way, it will give the speculation of this:

\displaystyle 15 = x^2

Now, in this case, since you were extra explanatory about this [what is written in parentheses], two factors I know of that multiply to 15 are these:

** \displaystyle 15 = 2 \times 7\frac{1}{2}

I am joyous to assist you at any time. ☺️

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The area of triangle ABC is _____. A 60 B65 C130 D150
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Is there a picture that goes with the question ?
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3 years ago
How do I do 8b(ii) ? Please help me thank you!
Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


7 0
3 years ago
Line m has an equation of y = 3x + 2
agasfer [191]

Answer:

Parallel= 3

Perpendicular= -1/3

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