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4vir4ik [10]
3 years ago
9

-4x^2+20-4 in standard form

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
4 0
The answer should be -4x^2+16               
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Factoring polynomial 40a2 -32a
Dafna1 [17]
40a^2 -32a
the GCF is 8a
Factoring out the 8a....
8a(5a - 4)
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4 years ago
What is the source of the energy for the circled movement of water?<br> I’ll mark brainliest
Vilka [71]
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4 years ago
Please write in slope intercept form I’m struggling <br><br> y+4=-7(x-3)
klemol [59]

Answer:

y = -7x + 17

Step-by-step explanation:

you want to isolate the 'y' variable, start by distributing -7 on the right side

y + 4 = -7x + 21

now subtract 4 from each side

y = -7x + 17

8 0
3 years ago
Read 2 more answers
3. Find the volume of the cylinder
liraira [26]
Diameter=16mm, so the radius is 8. The formula for volume of a cylinder is the area of the base times height, or v=πr²h.
Substituting the values in, we get π(8²)(5.7), which gives us roughly 1146mm^3.
4 0
3 years ago
The sides of a square all have a side length of y. Write a simplified area function in terms of y for a rectangle whose length i
gizmo_the_mogwai [7]

The simplified area function in terms of y for a rectangle is f(y)=2 y^{2}+4 y

<u>Solution:</u>

Given that length of each side of a square = y

Need to determine area of rectangle whose length is twice the length of the square and width is 2 units longer that the side length of square

Length of rectangle = twice of side length of square = 2 \times y = 2y

Width of rectangle = 2 + side length of square = 2 + y = y + 2

\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle.}

On substituting length and width in formula for area, we get

\text { Area of rectangle }=2 y \times (y+2)=2 y^{2}+4 y

Hence function f(y)=2 y^{2}+4 y is represents area of required rectangle.

3 0
3 years ago
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