Answer:
The sample of sizes 2 and their mean are given below.
Step-by-step explanation:
The population consist of 5 values, S = {1, 3, 4, 4, 6}.
The number of samples of size 2 (without replacement) that can be formed from these 5 values is:
Th formula to compute the mean is:
List the 10 samples and their mean as follows:
<u>Sample</u> <u>Mean</u>
(1, 3)
(1, 4)
(1, 4)
(1, 6)
(3, 4)
(3, 4)
(3, 6)
(4, 4)
(4, 6)
(4, 6)
X=3 and y=−3 is the answer
Answer:
I believe he answered 18 questions correctly.
<span>we have that
the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]
we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]
z1=3[cos 110° + i sin 110°]
cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]
z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is
</span>z1=3[cos 110° + i sin 110°]<span>
</span>z2=3[cos 230° + i sin 230°]
z3=3[cos 350° + i sin 350°]<span>
</span>
Y = kx where k is a constant
27 = k*9
k = 27/9 = 3
required variation is y = 3x