No. Because the Tenths place is right after the decimal. So he will only have 1 decimal place. Welcome!
Answer:
x^2+y^2=6^2
Step-by-step explanation:
The equation of a circle is (x-h)^2+(y-k)^2=r^2
where h is the x coordinate of the center, k is the y coordinate of the center, and r is the radius of the circle.
We can see the center is on 0,0, and the radius is 6, so our equation is
(x-0)^2+(y-0)^2=6^2
or
x^2+y^2=6^2
D) 48
2 packs of plates is 48 plates and 3 packs of cups os 48 plates.
1+1 will always be 2, which is greater than 1. Unless you had options, in which case please attach your options
c = number of children
s = number of students
a = number of adults
since the theater has a capacity of 189, then c + s + a = 189.
there are half as many "a" as "c", so then a = c/2 or 2a = c.
so the cost for all children since the price for one is 5 bucks, the total will be 5*c or 5c.
likewise, the total cost for students is 7*s or 7s.
and for adults likewise is 12*a or 12a.
we know all ticket sales was 1372, so then 5c + 7s + 12a = 1372.
![\bf \begin{cases} c+s+a=189\\ 5c+7s+12a=1372\\ 2a=\boxed{c} \end{cases}\qquad \implies \qquad \begin{cases} \boxed{2a}+s+a=189\\\\ 5\left( \boxed{2a} \right)+7s+12a=1372 \end{cases} \\\\\\ \begin{cases} 3a+s=189\\ 22a+7s=1372 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20c%2Bs%2Ba%3D189%5C%5C%205c%2B7s%2B12a%3D1372%5C%5C%202a%3D%5Cboxed%7Bc%7D%20%5Cend%7Bcases%7D%5Cqquad%20%5Cimplies%20%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cboxed%7B2a%7D%2Bs%2Ba%3D189%5C%5C%5C%5C%205%5Cleft%28%20%5Cboxed%7B2a%7D%20%5Cright%29%2B7s%2B12a%3D1372%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%203a%2Bs%3D189%5C%5C%2022a%2B7s%3D1372%20%5Cend%7Bcases%7D)
now, let's use the elimination method on that system of equations of two variables, let's multiply hmmmm say the first equation by -7, to eliminate the "s".
![\bf \begin{array}{llll} 3a+s=189&\times -7\implies &-21a-7s=-1323\\ 22a+7s=1372&&~~22a+7s=1372\\ \cline{3-3} &&~~ ~~ a+~~0=49 \end{array} \\\\\\ a=49\qquad \qquad \stackrel{\textit{recall c = 2a}}{c=98} \\\\\\ \stackrel{\textit{and plugging \underline{a} in the 1st equation}}{3(49)+s=189}\implies 147+s=189\implies s=42 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill a=49\qquad c=98\qquad s=42~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bllll%7D%203a%2Bs%3D189%26%5Ctimes%20-7%5Cimplies%20%26-21a-7s%3D-1323%5C%5C%2022a%2B7s%3D1372%26%26~~22a%2B7s%3D1372%5C%5C%20%5Ccline%7B3-3%7D%20%26%26~~%20~~%20a%2B~~0%3D49%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5C%5C%20a%3D49%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Ctextit%7Brecall%20c%20%3D%202a%7D%7D%7Bc%3D98%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Band%20plugging%20%5Cunderline%7Ba%7D%20in%20the%201st%20equation%7D%7D%7B3%2849%29%2Bs%3D189%7D%5Cimplies%20147%2Bs%3D189%5Cimplies%20s%3D42%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20a%3D49%5Cqquad%20c%3D98%5Cqquad%20s%3D42~%5Chfill)