F(x)=-2x+15 from x=0 to x=3 Find the average rates of change

Jeannie is an experienced business traveler, often traveling back and forth from San Francisco to the East Coast several times p

lesya692 [45]

Answer:

The probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour is 0.0026.

Jeannie should leave her office 55 minutes early.

Step-by-step explanation:

Let X = time it requires Jeannie to catch her plane.

The random variable X is normally distributed, $N(46, 5)$ .

Compute the probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour as follows:

$P(X>60)=P(\frac{X-\mu}{\sigma} >\frac{60-46}{5} )\\=P(Z>2.8)\\=1-P(Z$

The probability that Jeannie will miss her flight because her total time for catching her plane exceeds one hour is 0.0026.

Now, it is provided that Jeannie has 96% chance of catching her flight if she reaches under x minutes.

That is, P (X < x) = 0.96.

Compute the value of x as follows:

$P(X$

**Use the z-table to compute the value of z.

The value of z is 1.751.

Compute the value of x as follows:

$z=\frac{x-46}{5}\\ 1.751=\frac{x-46}{5}\\x=46+(1.751\times5)\\=54.755\\\approx 55$

Thus, Jeannie should leave her office 55 minutes early.

4 0

3 years ago

What does the geometry notation " A-B-C " mean?

stepladder [879]

Those usually mean the variable for the side length for a triangle.

7 0

3 years ago

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Marla’s School has 1,030 students. Kim’s school has 3 times as many students as Sandi’s School. Write an equation to find the nu

DENIUS [597]

Answer:

3090

Step-by-step explanation:

times 1,030 to 3.

6 0

3 years ago

A warehouse employs 22 workers on first shift and 14 workers on second shift. Eight workers are chosen at random to be interview

lara [203]

36 all together.
22 first
14 second
8 random chosen

A) all first shift:
One is pulled 22/36
Second is pulled 21/35
Third is pulled 20/34
Fourth 19/33
Fifth 18/32
Sixth 17/31
Seventh 16/30
Eighth 15/29

Multiply all those together
Probability of all first shift is 0.010567296996663
(That means it's not happening anytime soon lol)

B) one worker 14/36
Second 13/35
Third 12/34
Fourth 11/33
Fifth 10/32
Sixth 9/31
Seventh 8/30
Eighth 7/29

Multiply all those together
Probability of all second shift is 0.000099238805645
(That means it's likely to see 100x more picks of all first shift workers before you see this once.. lol)

C) 22/36
21/35
20/34
19/33
18/32
17/31

Multiply..
Probability.. 0.038306451612903

D) 14/36
13/35
12/34
11/33

X... p=0.016993464052288

Probably not correct, haven't done probability in years.

8 0

3 years ago

each evening, Marisol spend at least twice as much time reading as she spends doing homework. If Marisol works on her homework f

erica [24]

To get the result we can use knowledge that reading is 2 times longer than HW.
To find this value we just have to multiply 42 times 2 so
40*2=80
Its 1 hour and 20 min - its the result

8 0

3 years ago

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