Answer:
Step-by-step explanation:
log3(x^2)-log3(x+4)=4
Log 3(x^2/x+4)=4 -Combine the logs
x^2/x+4 = 3^4 - Use the relationship Logb(y)=x =>b^x=y
x^2/x+4 = 81
x^2= 81^(x+4)
x^2=81x+324
x^2-81x-324=0
Solving for x using the property x=-b-/+[tex]\sqrt{x} b^2-4ac]/ 2a
=(81 ±√(81)^2-4^11^324)/2
= (81±√6561-1296)/2
=(81±88.63)/2
= (81+88.63)/2
=84.81
Answer:
16
Step-by-step explanation:
Answer:
x = -2
Step-by-step explanation:
You would first distribute.
<u>6(3x + 7)</u> = <u>-5(4x - 3)</u> - 49 → 18x + 42 = -20x + 15 - 49
We can then calculate difference of 15 and 49.
18x + 42 = -20x <u>+ 15 - 49</u> → 18x + 42 = -20x -34
We can now move the variables to one side of the equation and the numbers on the other side.
18x + 20x + 42 - 42 = -20x + 20x - 34 - 42 → 38x = -76
Then, divide.
38x ÷ 38 = -76 ÷ 38 → x = -2
Answer:
b
Step-by-step explanation:
3 x 5=15
15 x 9= 135
135=b