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2 years ago

(a) Write 0.3% as a decimal. (b) Write 1.32 as a percentage.

2 answers:

6 0

Please someone helpppp I feel like I can’t do this I can’t I feel sick my bone are aching

In a short narrative, write about the journey of a ribosome through transcription to translation to a protein, Explain the main process of Protein Synthesis from the perspective of a ribosome

include these vocabulary words:

Protein Synthesis, Amino Acid, Codon, Anticodon, Nucleotide, RNA: mRNA/ rRNA/tRNA DNA, RNA Polymerase, Transcription, Translation, Polypeptide, Genetic Code, Protein

kramer2 years ago

4 0

Answer:

(a) 0.003

(b) 132%

Step-by-step explanation:

(a) A percentage is basically a fraction over a hundred. 0.3/100 = 0.003

(b) 1.32 is a whole and .32. 100 + 32= 132%

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Given f(x)=5-3x, if f(x)=-19, find x

Dafna1 [17]

X would equal 8

Step-by-step explanation:

5-3(8) = -19

5 multiplied by negative 3 times 8 equals negative 19

negative 3 times 8 equals negative 24 plus 5 equals 19

7 0

2 years ago

10 points! Please help ASAP.

DerKrebs [107]

Answer: Yes
Explanation:
120 % = 1.2

If Maxine is correct, then she spent 1.2
times the hours she did homework than last week.
15 ⋅ 1.2 = 18.0 = 18

15 hours ⋅ 1.2 = 18.0 hours = 18 hours
Maxine is correct

6 0

2 years ago

Compute the slope of the line intersecting the points (1, 2) and (3, 8). *

DiKsa [7]

Answer:

slope = 3

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (1, 2) and (x₂, y₂ ) = (3, 8)

m = $\frac{8-2}{3-1}$ = $\frac{6}{2}$ = 3

6 0

2 years ago

HELP I need to fine the slope-intercept form. Please it’s a timed assignment I only have two try’s and I already used one

barxatty [35]

Answer:

5. y = -1/2x + 6

6. y = 1/2x + 150

7. y = 10x + 20

8. y = 25x

Step-by-step explanation:

Look at the y-intercept and eliminate the answers you dont need.

Then find the slope of each.

8 0

2 years ago

A swimming pool with a volume of 30,000 liters originally contains water that is 0.01% chlorine (i.e. it contains 0.1 mL of chlo

SpyIntel [72]

Answer:

$R_{in}=0.2\dfrac{mL}{min}$

$C(t)=\dfrac{A(t)}{30000}$

$R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}$

$A(t)=300+2700e^{-\dfrac{t}{1500}},$ A(0)=3000$

Step-by-step explanation:

The volume of the swimming pool = 30,000 liters

(a) Amount of chlorine initially in the tank.

It originally contains water that is 0.01% chlorine.

0.01% of 30000=3000 mL of chlorine per liter

A(0)= 3000 mL of chlorine per liter

(b) Rate at which the chlorine is entering the pool.

City water containing 0.001%(0.01 mL of chlorine per liter) chlorine is pumped into the pool at a rate of 20 liters/min.

$R_{in}=$ (concentration of chlorine in inflow)(input rate of the water)

$=(0.01\dfrac{mL}{liter}) (20\dfrac{liter}{min})\\R_{in}=0.2\dfrac{mL}{min}$

Volume of the pool =30,000 Liter

$Concentration, C(t)= \dfrac{Amount}{Volume}\\C(t)=\dfrac{A(t)}{30000}$

(d) Rate at which the chlorine is leaving the pool

$R_{out}=$ (concentration of chlorine in outflow)(output rate of the water)

$= (\dfrac{A(t)}{30000})(20\dfrac{liter}{min})\\R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}$

(e) Differential equation representing the rate at which the amount of sugar in the tank is changing at time t.

$\dfrac{dA}{dt}=R_{in}-R_{out}\\\dfrac{dA}{dt}=0.2- \dfrac{A(t)}{1500}$

We then solve the resulting differential equation by separation of variables.

$\dfrac{dA}{dt}+\dfrac{A}{1500}=0.2\\$The integrating factor: e^{\int \frac{1}{1500}dt} =e^{\frac{t}{1500}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{1500}}+\dfrac{A}{1500}e^{\frac{t}{1500}}=0.2e^{\frac{t}{1500}}\\(Ae^{\frac{t}{1500}})'=0.2e^{\frac{t}{1500}}$

Taking the integral of both sides

$\int(Ae^{\frac{t}{1500}})'=\int 0.2e^{\frac{t}{1500}} dt\\Ae^{\frac{t}{1500}}=0.2*1500e^{\frac{t}{1500}}+C, $(C a constant of integration)\\Ae^{\frac{t}{1500}}=300e^{\frac{t}{1500}}+C\\$Divide all through by e^{\frac{t}{1500}}\\A(t)=300+Ce^{-\frac{t}{1500}}$

Recall that when t=0, A(t)=3000 (our initial condition)

$3000=300+Ce^{0}\\C=2700\\$Therefore:\\A(t)=300+2700e^{-\dfrac{t}{1500}}$

3 0

2 years ago