Answer:
W = 15900 ft.lb
Step-by-step explanation:
From the given information.
Consider y to be the distance from the ground towards the bucket of the cement.
At height y, suppose the bucket is lifted by Δy.
Then, the workdone can be = 500Δy + 0.5(75 - y) Δy
where;
The bucket of the cement = 500Δy
The remaining of the rope = 0.5(75 - y) Δy
However; the workdone (W) can be calculated as:
W = 15000 + 0.5 ( 2250 - 450)
W = 15000 + 900
W = 15900 ft.lb
Steps:
(x-2)=4x
Pretend that there is a one in front of x-2
1(x-2)=4x
Multiply the bracket by 1
x-2=4x
Move x to the other side .Whenever you move a number or letter the sign changes.
x-x-2=4x-x
-2=3x
Divide by 3 for -2 and 3
-2/3=3/3 x
x=-2/3
Check answer by using substitution method
(-2/3-2)=4(-2/3)
(-2/3-6/3)=-8/3
-8/3=-8/3
Answer is -2/3
The diagram of the triangle is shown below
One interior angle is 56°
One exterior angle is 103° ⇒ we can work out one interior angle 180°-103° = 77°
The other interior angle is 180° - (56°+77°) = 44°
Answer:
86
Step-by-step explanation:
