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OleMash [197]
3 years ago
11

ALOT OF PONTS!!! HELPPP!!! Hi, I would greatly appreciate help with this. I have no idea how to do it.

Mathematics
1 answer:
Digiron [165]3 years ago
7 0

Answer:

Logically, the answer is the sphere, as it is the figure which gives maximum volume for the same total surface area. But I'll just solve them like you want it.

I'm just writing the numerical values without the units.Please resolve

Solid 1: Square Prism with each side of the base equal to 8 in. and a height of 8 in.

Volume = 8^3 = 512

Area = 8^2 * 6 = 384

V/A Ratio = 1.33 (We need the highest ratio, that's why they hired us)

Cost = $7.68

Solid 2: Square Pyramid with each side of the base equal to 10 in. and a height of 15 in.

Volume = 1/3 * 10^2 * 15 = 500

Slant height = [(10/2)^2 + 15^2]^(1/2) = root of 250 = 15.81

Area = 2*10*15.81 + 10^2 = 416.23

V/A Ratio = 1.20

Cost = $8.34

Solid 3: Cylinder with a radius of 4 in. and a height of 10 in.

Volume = pi*4*4*10 = 502.65

Area = 2*pi*4*4 + 2*pi*4*10 = 351.86

V/A Ratio = 1.43

Cost = $7.04

Solid 4: Cone with a radius of 7 in. and a height of 10 in.

Volume = (1/3)*pi*7*7*10 = 513.13

Slant height = [(7^2)+(10^2)]^(1/2) = 12.21

Area = pi*7*12.21 + pi*7*7 = 422.37

V/A Ratio = 1.21

Cost = $8.45

Solid 5: Sphere with a radius of 5 in.

Volume = (4/3)*pi*(5^3) = 523.60

Area = 4*pi*(r^2) = 314.16

V/A Ratio = 1.67

Cost = $6.28

Hence, Solid 5 must be the packaging model opted for

Step-by-step explanation:

Logically, the answer is the sphere, as it is the figure which gives maximum volume for the same total surface area. But I'll just solve them like you want it.

I'm just writing the numerical values without the units.Please resolve

Solid 1: Square Prism with each side of the base equal to 8 in. and a height of 8 in.

Volume = 8^3 = 512

Area = 8^2 * 6 = 384

V/A Ratio = 1.33 (We need the highest ratio, that's why they hired us)

Cost = $7.68

Solid 2: Square Pyramid with each side of the base equal to 10 in. and a height of 15 in.

Volume = 1/3 * 10^2 * 15 = 500

Slant height = [(10/2)^2 + 15^2]^(1/2) = root of 250 = 15.81

Area = 2*10*15.81 + 10^2 = 416.23

V/A Ratio = 1.20

Cost = $8.34

Solid 3: Cylinder with a radius of 4 in. and a height of 10 in.

Volume = pi*4*4*10 = 502.65

Area = 2*pi*4*4 + 2*pi*4*10 = 351.86

V/A Ratio = 1.43

Cost = $7.04

Solid 4: Cone with a radius of 7 in. and a height of 10 in.

Volume = (1/3)*pi*7*7*10 = 513.13

Slant height = [(7^2)+(10^2)]^(1/2) = 12.21

Area = pi*7*12.21 + pi*7*7 = 422.37

V/A Ratio = 1.21

Cost = $8.45

Solid 5: Sphere with a radius of 5 in.

Volume = (4/3)*pi*(5^3) = 523.60

Area = 4*pi*(r^2) = 314.16

V/A Ratio = 1.67

Cost = $6.28

Hence, Solid 5 must be the packaging model opted for

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Answer: The correct number of balls is (b) 4.

Step-by-step explanation:  Given that a single winner is to be chosen in a random draw designed for 210 participants. Also, there is an equal probability of winning for each participant.

We are using 10 balls, numbered through 0 to 9. We are to find the number of balls which needs to be picked up, regardless of order, so that each of the 210 participants can be assigned a unique set of numbers.

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If r = 2, then

^{10}C_2=\dfrac{10!}{2!(10-2)!}=\dfrac{10!}{2!8!}=\dfrac{10\times 9\times 8!}{2\times 1\times 8!}=45

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If r = 4, then

^{10}C_4=\dfrac{10!}{4!(10-4)!}=\dfrac{10!}{4!6!}=\dfrac{10\times 9\times 8\times\times 7\times 6!}{4\times 3\times 2\times 1\times 6!}=210.

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