In order to find b1 from your formula stated we need to do few calculations
A=hb1+hb2, as you wee I multiply h with both bases( b1 and b2)
I will subtract hb2 from both sides
hb1=A-hb2
now I will divide my new expression by h
b1=(A-hb2)/h

8 0

3 years ago

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Which of the relations given by the following sets of ordered pairs is a function?

KonstantinChe [14]

9514 1404 393

Answer:

(a) {(5, 2), (-4, 2), (3, 6), (0, 4), (-1, 2)}

Step-by-step explanation:

The only relation with no repeated x-values is the first one. The first relation is a function.

6 0

3 years ago

8. There are 10 balls in a bag numbered from 1 to 10. Three balls are selected at random without replacement.

PIT_PIT [208]

Answer:

a. 720

b. 0.3

Step-by-step explanation:

Three balls are selected at random without replacement.

First ball can be selected in 10 ways

Second ball can be selected in 9 ways

Third ball can be selected in 8 ways

Thus, there are 10×9×8 =720 different ways of selecting three balls.

There are three cases that satisfy this condition

first ball picked is 5, the others are not
first ball is not 5, second is 5, third is not
first and second ball is not five, third ball is 5

Each probabilities are:

$\frac{1}{10} * \frac{9}{9} *\frac{8}{8} =\frac{1}{10}$
$\frac{9}{10} *\frac{1}{9} *\frac{8}{8} =\frac{1}{10}$
$\frac{9}{10} *\frac{8}{9} *\frac{1}{8} =\frac{1}{10}$

Thus, one of the balls selected is the number 5 is then $\frac{1}{10} + \frac{1}{10} + \frac{1}{10} = \frac{3}{10}$

5 0

3 years ago