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ikadub [295]
3 years ago
11

George found that he blinked 85 times in 15 minutes. At this rate, how many SECONDS passed during 51 blinks?

Mathematics
1 answer:
Nady [450]3 years ago
6 0
To solve this first we have to find out how many seconds are in 15 minutes.
So, 15 x 60 since there is 60 seconds in a minute, and of course there are 15 minutes.

15 x 60 = 900 seconds.

Now we need to find out about how many seconds does it take George to blink once. So we divide 900 seconds by 85 blinks.

900 / 85 = About 11 seconds for one blink.

Now we use the rate of 1 blink = 11 seconds and multiply. Since they said 51 blinks you would multiply 51 blinks by 11 seconds.

51 x 11 = About 561 seconds.

Answer: About 561 seconds passed in 51 blinks.

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Jennie purchased a box of crackers from the deli. The box is in the shape of a triangular prism. If the volume of the box is 3,2
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Answer:

Height of the triangular face of the box is 12 cm.

Step-by-step explanation:

This question is not complete; please find the question as the attachment.

Volume of a triangular prism = Area of the triangular base × height

It's given in the question, Volume of the prism = 3240 cm³

Height of the prism = 30 cm

By substituting these values in the formula,

3240 = B × 30

B = \frac{3240}{30}

B = 108 cm²

Area of the triangular face (B) = \frac{1}{2}(\text{Base})\times (\text{Height of the triangular base})

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108 = 9h

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Therefore, height of the triangular face of the prism is 12 cm.                                        

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