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viva [34]
3 years ago
10

The Elmina Wilson Company produces spaghetti sauce that is used in restaurants. The fixed costs total $1,329,050. The selling pr

ice per 64 oz. Can of sauce is $12.40. The variable cost per can is $4.80. What is the break-even point in number of cans?
Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
7 0

Answer:

174879 units

Step-by-step explanation:

Given that The Elmina Wilson Company produces spaghetti sauce.

Fixed costs =1,329,050 $

Selling price per  64 oz=12.40

Variable cost per can   = 4.80

Contribution = S-V=Selling price - var cost = 7.60 $

Break even poin in no of units = Fixed cost/Contribution per unit

=\frac{1,39,050}{7.60} \\=174878.94\\=174879

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Cosθ=−2√3 , where π≤θ≤3π2 .
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Answer:

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Step-by-step explanation:

step 1

Find the  sin(\theta)

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Applying the trigonometric identity

sin^2(\theta)+ cos^2(\theta)=1

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substitute

sin^2(\theta)+ (-\frac{\sqrt{2}}{3})^2=1

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sin^2(\theta)=1- \frac{2}{9}

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π≤θ≤3π/2

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Angle θ belong to the III Quadrant

That means ----> The sin(θ) is negative

sin(\theta)=-\frac{\sqrt{7}}{3}

step 2

Find the sec(β)

Applying the trigonometric identity

tan^2(\beta)+1= sec^2(\beta)

we have

tan(\beta)=\frac{4}{3}

substitute

(\frac{4}{3})^2+1= sec^2(\beta)

\frac{16}{9}+1= sec^2(\beta)

sec^2(\beta)=\frac{25}{9}

sec(\beta)=\pm\frac{5}{3}

we know

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so

sec(β), sin(β) and cos(β) are positive

sec(\beta)=\frac{5}{3}

Remember that

sec(\beta)=\frac{1}{cos(\beta)}

therefore

cos(\beta)=\frac{3}{5}

step 3

Find the sin(β)

we know that

tan(\beta)=\frac{sin(\beta)}{cos(\beta)}

we have

tan(\beta)=\frac{4}{3}

cos(\beta)=\frac{3}{5}

substitute

(4/3)=\frac{sin(\beta)}{(3/5)}

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sin(\beta)=\frac{4}{5}

step 4

Find sin(θ+β)

we know that

sin(A + B) = sin A cos B + cos A sin B

so

In this problem

sin(\theta + \beta) = sin(\theta)cos(\beta)+ cos(\theta)sin (\beta)

we have

sin(\theta)=-\frac{\sqrt{7}}{3}

cos(\theta)=-\frac{\sqrt{2}}{3}

sin(\beta)=\frac{4}{5}

cos(\beta)=\frac{3}{5}

substitute the given values in the formula

sin(\theta + \beta) = (-\frac{\sqrt{7}}{3})(\frac{3}{5})+ (-\frac{\sqrt{2}}{3})(\frac{4}{5})

sin(\theta + \beta) = (-3\frac{\sqrt{7}}{15})+ (-4\frac{\sqrt{2}}{15})

sin(\theta + \beta) = -\frac{\sqrt{7}}{5}-4\frac{\sqrt{2}}{15}

8 0
4 years ago
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