Blue beads: 100/130, which reduces to 10/13.
Red beads: 20/130, which reduces to 2/13.
You're just taking the fraction of the certain color of beads compared with the total number of beads, which is 130.
its bella saves more per chore than sweet tea, because 3.5 x c = the amount of chores bella does. Add 11 to that, and she will get more than Sweet Tea. for Sweet tea, one chore saves her twelve dollars. For Bella, one chore saves her more.
Answer:
![\left[\begin{array}{ccc}3&-5 &|12\\4&-2 &|15\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%20%20%26%7C12%5C%5C4%26-2%20%20%26%7C15%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
When making a matrix of two equations with the variables x and y, the result will be a matrix with three columns:
- a column for the values of x in each equation
- a column for the values of y in each equation
- a column for the independent values of each equation
since our system of equations is:
![3x-5y=12\\ 4x-2y=15](https://tex.z-dn.net/?f=3x-5y%3D12%5C%5C%204x-2y%3D15)
we can see that the value for x in the first equation is 3 and in the second equation is 4, thus the first column will have the numbers 3 and 4:
![\left[\begin{array}{ccc}3&&\\4&&\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26%26%5C%5C4%26%26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Now for the values of y we hvae -5 in the first equation and -2 in the second equation, we update the matrix with another column with the values of -5 and -2:
![\left[\begin{array}{ccc}3&-5&\\4&-2&\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%26%5C%5C4%26-2%26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Finally, the last column is the independent values of each equation (or the results) in the first equation that number is 12 and in the second equation is 15, thus the matrix is:
![\left[\begin{array}{ccc}3&-5&12\\4&-2&15\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%2612%5C%5C4%26-2%2615%5C%5C%5Cend%7Barray%7D%5Cright%5D)
usually there is a line separating the columns for the values of x and y, and the independent values:
![\left[\begin{array}{ccc}3&-5 &|12\\4&-2 &|15\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%20%20%26%7C12%5C%5C4%26-2%20%20%26%7C15%5C%5C%5Cend%7Barray%7D%5Cright%5D)
this is the matrix of the system of equations
In the first step when the student did -2x-3 they didn’t make the sign positive. It should be 4=-2+6, not 4=-2-6
Answer:
The question is incomplete, this is the complete question.;
There are five nickels, five dimes and five quarters in your pocket. You randomly pick three coins and place them on the counter the first coin is a nickel, the second is a dime and the third is a quarter.find the probability of this occurring.
The answer to the question is;
the probability of this occurring is 1/27
Step-by-step explanation:
Let n(N) =5 ( the number of nickels)
n(D) =5 ( the number of dimes) and
n(Q) = 5 ( the number of quarters)
P(N)= 5/15=1/3 (prob of picking a nickel)
P(D) =5/15=1/3 (prob of picking a dime)
P(Q) = 5/15= 1/3 (prob of picking a quatre)
The probability of picking the three= P(N)×P(D)×P(Q)
= 1/3×1/3×1/3
= 1/27